Solving a Parallel-Plate Capacitor Problem

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SUMMARY

The discussion revolves around calculating the capacitance of a parallel-plate capacitor with circular plates of 6.00 cm radius and 2.00 mm separation. The correct formula for capacitance is given by C = (ε₀ × Area) / distance, where ε₀ is the permittivity of free space (8.85E-12 F/m). The area of a circle is calculated using A = πr², not 4πr², leading to the correct capacitance value of approximately 200.2 pF when using the proper area calculation.

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bbbbbev
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Hi. I have this seemingly easy problem that I cannot get the right answer to! Here it is:

A parallel-plate capacitor has circular plates of 6.00 cm radius and 2.00 mm separation.
Calculate the capacitance.

Ok, so I thought the formula for capacitance was [(epsilon)_0 x Area]/distance = capacitance

So I tried: [(8.85E-12 F/m)(4(pi)(0.06m)^2)]/0.002m = 200.2 pF

I cannot figure out what I am doing wrong. That formula is in the book! Am I overlooking something? Thanks in advance for any help you can give!

Beverly
 
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The area of a circle isn't 4*pi*r^2. :)
 
Aggh! I'm such an idiot! What was I thinking? Haha, Thanks!
 

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