Calculating Stopping Distance: 50km/h vs 150km/h Car Speeds

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Discussion Overview

The discussion revolves around calculating the stopping distance of a car based on its speed, specifically comparing a car skidding to a halt from 50 km/h and 150 km/h. The scope includes theoretical reasoning and mathematical calculations related to physics concepts such as kinetic energy and friction.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant states that if a car skids to a halt from 50 km/h over 20 m, then at 150 km/h, the stopping distance would be 180 m based on the relationship between kinetic energy and speed.
  • Another participant challenges the initial claim about the type of friction involved, arguing that skidding implies kinetic friction, not static friction.
  • A further reply suggests that the actual stopping distance would be less than 180 m due to the effects of air resistance, which is not linearly dependent on speed.

Areas of Agreement / Disagreement

Participants express differing views on the calculations and the type of friction involved in skidding. There is no consensus on the stopping distance or the effects of air resistance.

Contextual Notes

The discussion includes assumptions about the forces acting on the car and the simplifications made in the calculations. The impact of air resistance on stopping distance remains unresolved.

janes3kids@yahoo.com
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I got this one wrong on a test and I am debating it.
A car going 50 km/h skids to a halt going 20m. If the same car is going 150km/h how far will it skid til it comes to a halt.
a)20m b) 60m c) 180m
 
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janes3kids@yahoo.com said:
I got this one wrong on a test and I am debating it.
A car going 50 km/h skids to a halt going 20m. If the same car is going 150km/h how far will it skid til it comes to a halt.
a)20m b) 60m c) 180m
The car does work in skidding: Work = Force*distance where Force is the kinetic friction force. Friction is a function of the normal force, which does not change. So Work is proportional to Distance of the skid.

The car's ability to do work is its kinetic energy. KE = W. Since [itex]KE = \frac{1}{2}mv^2[/itex] if you triple v, its energy goes up by a factor 3^2=9. So the distance of skid is 9 x 20 = 180 m.

AM
 
Don't mean to be picky but since the car is 'skidding', the tires arent moving and its static friction.

<3 AM
 
whozum said:
Don't mean to be picky but since the car is 'skidding', the tires arent moving and its static friction.
"skidding" implies that the tires slide against the ground (the wheels are locked), so there is slipping between the contact surfaces and kinetic friction applies. If the car stopped without skidding, then the tires would roll without slipping and static friction would apply.
 
in fact it is less than 180 m due to the heigher-than-linear-order-dependence of air resistance force on velocity... how much exactly it differs depends on the car shape.
 

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