Find diameter of steel wire - stress

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SUMMARY

The diameter of a steel wire measuring 18 meters in length, which elongates by 9 mm under a load of 380 kg, is calculated to be 6.8859 mm. The calculations utilize the formula for elongation, ΔL = FL/YA, leading to an area A of 3.724E-5 m². The stress applied to the wire is determined to be 1.00 x 10^8 N/m², which is below the elastic limit of 3.00E8 N/m², indicating that no permanent deformation occurs. The calculations and conclusions presented are accurate and consistent with the principles of material science.

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UrbanXrisis
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a) what is the diameter of a steel wire 18m long that elongates 9mm when a load of 380kg is hung on its end?
b) if the elastic limit is 3.00E8 N/m^2, does permanent deformtion occur?

a.
[tex]\Delta L=FL/YA[/tex]
[tex]9E-3m=\frac{3724N*18m}{20E10N/m^2*A}[/tex]
[tex]A=3.724E-5m^2[/tex]
[tex]diameter=6.8859mm[/tex]

b.
[tex]stress=F/A[/tex]
[tex]stress=\frac{3724N}{3.724E-5m^2}[/tex]
[tex]stress=1.00x10^8N/m^2[/tex]
no deformation

is that all correct?
 
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Looks good to me!
 


Yes, your calculations and answers appear to be correct. However, it is always a good idea to double check your work and make sure all units are consistent. Additionally, it would be helpful to provide a clear explanation of the steps and equations used to arrive at your answers. This will ensure that others can follow your reasoning and understand your solution.
 

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