Check the equation of the circle

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Homework Help Overview

The discussion revolves around the equations of circles, specifically focusing on determining the correct form based on given centers and points. The original poster presents two problems involving circles with specified centers and points through which they pass.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to derive the equations of circles based on the center and a point, raising questions about the correctness of their calculations. Some participants question the necessity of finding a midpoint and the method used to calculate the radius.

Discussion Status

Participants have provided feedback on the original poster's equations, with some confirming the correctness of the second equation while others suggest corrections to the first. The discussion reflects an ongoing exploration of the problem without reaching a definitive conclusion on the first equation initially proposed.

Contextual Notes

There is a mention of the radius being calculated incorrectly in the initial post, and the center of the circle is explicitly provided, which some participants note as a point of confusion. The discussion also highlights the importance of accurately interpreting the problem requirements.

aisha
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check please the equation of the circle

the Center is C(-1,2) and the x intercept is 3

I found the distance between the center and the point to be r^2=10

and the midpoint of the two given points to be (1,1)

therefore my final equation for this circle is

[tex](x-1)^2 + (y-1)^2 =10[/tex]

is my answer correct? Any objections? :-p

Another question Equation of a circle with center (4,-3) that passes through the point (2,1)

for this question I got [tex](x-4)^2 + (y+3)^2 =20[/tex]

Is this one right?
 
Last edited:
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Unfortunately not quite. You don't need to find any midpoint at all: the center is given.

Also I don't like your radius. It should just be the distance between the two given points (which I calculate to be [itex]\sqrt{20}[/itex]).
 
Your answer to the second question is correct.
 
oops ok I got my new answer to be

[tex](x+1)^2 + (y-2)^2 = 20[/tex]

is this correct now can you also check the second question in the first post? :redface:
 
Yep, they're both right now. :smile:
 

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