Calculating Convergent Series: Tips for $\sum_{n=1}^{\infty} n^2 w^n$

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Homework Help Overview

The discussion revolves around the summation of the series \(\sum_{n=1}^{\infty} n^2 w^n\), specifically within the context of its convergence for \(|w| < 1\).

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore methods to sum the series, with suggestions to leverage its similarity to a geometric series and to consider differentiation as a potential approach.

Discussion Status

Some participants have provided hints and partial derivations related to the series, while others express a need for clarification on how to properly format summations and powers.

Contextual Notes

There are indications of participants seeking guidance on notation and formatting, as well as a focus on the mathematical manipulation of the series without reaching a definitive conclusion.

cepheid
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Does anyone have tips on how to sum the following series?

[tex]\sum_{n=1}^{\infty} n^2 w^n[/tex]

Region of convergence is for |w| < 1
 
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Try to exploit it's similarity with a geometric series.
Hint: Differentiate.
 
cepheid said:
Does anyone have tips on how to sum the following series?

[tex]\sum_{n=1}^{\infty} n^2 w^n[/tex]

Region of convergence is for |w| < 1

[tex](1) \ \ \ \ z \ = \ \sum_{n=0}^{\infty} w^{n} \ = \ (1 \ - \ w)^{-1} \ =[/tex]

[tex](2) \ \ \ \ \ \ \ \ \ \ = \ 1 \ + \ w \ + \ \sum_{n=2}^{\infty} w^{n}[/tex]

[tex]3 \ \ \ \ \ \ \frac {dz} {dw} \ = \ \left ( 1 \ - \ w \right )^{-2} =[/tex]

[tex](4) \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \ 1 \ \ + \ \ \sum_{n=2}^{\infty} n \cdot w^{n-1} \ = \ 1 \ \ + \ \ w^{-1} \cdot \sum_{n=2}^{\infty} n \cdot w^{n}[/tex]

[tex](5) \ \ \ \ \ \Longrightarrow \ \sum_{n=2}^{\infty} n \cdot w^{n} \ = \ w \cdot \left( \left(1 \ - \ w \right)^{-2} \ - \ 1 \ \right)[/tex]

[tex]6 \ \ \ \ \ \ \frac {d^{2}z} {dw^{2}} \ = \ 2 \cdot \left ( 1 \ - \ w \right )^{-3} \ =[/tex]

[tex](7) \ \ \ \ \ \ \ \ \ \ = \ \sum_{n=2}^{\infty} n \cdot ( n \ - \ 1 ) \cdot w^{n-2} \ =[/tex]

[tex](8) \ \ \ \ \ \ \ \ \ \ = \ w^{-2} \cdot \sum_{n=2}^{\infty} n \cdot ( n \ - \ 1 ) \cdot w^{n} \ =[/tex]

[tex](9) \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \ w^{-2} \cdot \left ( \sum_{n=2}^{\infty} n^{2} \cdot w^{n} \ - \ \sum_{n=2}^{\infty} n \cdot w^{n} \right ) \ =[/tex]

[tex](10) \ \ \ \ \ \ \ \ \ \ \ = \ w^{-2} \cdot \left ( \sum_{n=2}^{\infty} n^{2} \cdot w^{n} \ - \ w \cdot \left( \left(1 \ - \ w \right)^{-2} \ - \ 1 \ \right) \right ) \[/tex]

[tex](11) \ \ \ \ \color{red} \Longrightarrow \ \sum_{n=2}^{\infty} n^{2} \cdot w^{n} \ = \ 2 \cdot w^{2} \cdot \left ( 1 \ - \ w \right )^{-3} \ \ + \ \ w \cdot \left( \left(1 \ - \ w \right)^{-2} \ - \ 1 \ \right)[/tex]

[tex](12) \ \ \ \ \color{red} \Longrightarrow \ \sum_{n=1}^{\infty} n^{2} \cdot w^{n} \ \ = \ \ w \ \ + \ \ 2 \cdot w^{2} \cdot \left ( 1 \ - \ w \right )^{-3} \ \ + \ \ w \cdot \left( \left(1 \ - \ w \right)^{-2} \ - \ 1 \ \right)[/tex]



~~
 
Last edited:
Just Wanted To Know How To Make The Summation And Powers
 
Last edited:

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