3rd order low pass Butterworth active filter

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Discussion Overview

The discussion revolves around the design of a 3rd order low pass Butterworth active filter with a specified cutoff frequency of 8 kHz. Participants explore the theoretical and practical aspects of filter design, including the order of the filter and the necessary components.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant inquires about the design of a 3rd order low pass Butterworth active filter with a cutoff frequency of 8 kHz.
  • Another participant questions the existence of a 3-pole Butterworth filter, expressing doubt about its validity.
  • A different participant provides a polynomial representation of a 3rd order Butterworth filter, suggesting a mathematical approach to the design.
  • One participant critiques the initial design, noting that the first stage is a second order filter and the second stage is a first order filter, and emphasizes the importance of component selection for achieving the desired Butterworth characteristics.

Areas of Agreement / Disagreement

Participants express differing views on the existence and definition of a 3rd order Butterworth filter, indicating a lack of consensus on this aspect of the discussion.

Contextual Notes

There are unresolved questions regarding the definitions and assumptions related to filter orders and the specific design requirements for achieving a Butterworth response.

tinhnho
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Hi everyone

Does anyone know how to design a 3rd order low pass Butterworth active filter with a cutoff frequency of 8khz ? thanks

p/s: Attachment below is what i have
 

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When you say "3rd order" do you mean 3-pole? I have never seen a 3-pole Butterworth filter, and doubt that such a thing exists.

- Warren
 
3rd other butterworth polynomial:
(s+1)(s^2+s+1)

4th order:
(s^2+.765s+1)(s^2+1.848s+1)

etc...
 
Your first stage is a second order filter and the second stage is a first order filter. In each stage you should choose R and C such as 1/RC = 2πx8x103.
Only, in order to have a Butterworth filter you should not have a unit gain amplifier in the first stage. According to your table, the gain of that stage should be 3 - 1 = 2.
 

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