Prove CD/AB=DE/AE when A=D in Diagram

  • Context: Undergrad 
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Discussion Overview

The discussion revolves around proving the relationship CD/AB = DE/AE under the condition that Angle A equals Angle D, as illustrated in a provided diagram. The focus is on the properties of triangles ABE and EDC, exploring concepts of congruence and similarity.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant asks how to prove the ratio CD/AB = DE/AE given that Angle A equals Angle D.
  • Another participant notes that if Angle A equals Angle D, it leads to a consideration of the triangles ABE and EDC.
  • A participant suggests that Angle AEB equals Angle DEC and that Angle ABE equals Angle DCE, proposing that this indicates the triangles are congruent.
  • Another participant counters that the triangles can be considered similar, allowing for the use of the proportion law to derive the desired result.

Areas of Agreement / Disagreement

Participants present differing views on whether the triangles are congruent or similar, indicating that there is no consensus on the approach to proving the relationship.

Contextual Notes

The discussion does not resolve the assumptions regarding the conditions under which the triangles are considered congruent or similar, nor does it clarify the implications of these properties on the proof.

powp
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How do you prove that CD/AB = DE/AE when Angle A = Angle D in the attached Diagram??

THanks
 

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Here is the image
 

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if angle A = angle D
what can u say about the triangles ABE and EDC?
what conclusion can u make?
 
Not sure I am wrong but here is my first thoughts

Angle AEB = Angle DEC

Therefore Angle ABE = Angle DCE

which means that the two triangles are congruant

This is my tought
 
u can get to say that those triangles are similar
so u can use the proportion law
and obtain the result
ok?
 

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