Effect of Sudden Radial Velocity Change on Orbital Energy and Angular Momentum

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SUMMARY

The discussion focuses on the effects of a sudden radial velocity change on a communications satellite's orbital energy and angular momentum. The equations governing the satellite's energy and angular momentum are provided, specifically E = 1/2*mu*v^2 + L^2/(2*mu*R^2) - k/R for energy, where mu is the reduced mass, L is angular momentum, and k = G*m1*m2. The participants analyze how the radial velocity affects the satellite's trajectory and the calculations needed to determine the new orbit radius and energy ratios. Key concepts include effective potential and the relationship between kinetic and potential energy in orbital mechanics.

PREREQUISITES
  • Understanding of orbital mechanics and satellite dynamics
  • Familiarity with the concepts of kinetic energy and potential energy
  • Knowledge of angular momentum and its conservation
  • Ability to work with gravitational equations, specifically G*m1*m2
NEXT STEPS
  • Calculate the new orbital radius after a radial velocity change using conservation laws
  • Explore the concept of effective potential and its role in orbital stability
  • Learn how to plot kinetic and potential energy functions in orbital mechanics
  • Investigate the implications of torque on angular momentum in satellite motion
USEFUL FOR

Aerospace engineers, astrophysicists, and students studying orbital mechanics will benefit from this discussion, particularly those interested in satellite dynamics and energy conservation principles in physics.

asrodan
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A communications satellite is in a circular orbit around Earth at radius R and velocity v. A rocket accidently fires quite suddenly, giving the satellite an outward radial velocity v in addition to its original velocity.

a) Calculate the ratio of the new energy to the old and new angular momentum to the old.

b) Describe the subsequent motion of the satellite and plot T(r), V(r), U(r), and E(r) after the rocket fires.

I'm not sure how to do this question.

For a) E = 1/2*mu*v^2 + L^2/(2*mu*R^2) - k/R where mu is reduced mass, L is angular momentum k = G*m1*m2, and E is the total energy.

The v in the first term is for radial velocity only, so it is zero initially because there is no radial velocity in a circular orbit. The energy after the rocket fires, but before any radial position change is equal to the equation as written.

For angular momentum to change without any additional tangential velocity there has to be a radial position change. But I'm not sure how to figure out the radius of the new orbit that the satellite would attain.

For b) T(r) is the kinetic energy, I'm not sure how to plot this since the kinetic energy has a dependence on the derivative of r.

V(r) is the effective potential, consisting of the second two terms in the above energy equation.

U(r) is just the gravitational potential energy.

E(r) is the total energy.


Could someone help please?
 
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asrodan said:
A communications satellite is in a circular orbit around Earth at radius R and velocity v. A rocket accidently fires quite suddenly, giving the satellite an outward radial velocity v in addition to its original velocity.

a) Calculate the ratio of the new energy to the old and new angular momentum to the old.
The new energy is:

[tex]E = U(R) + \frac{1}{2}m(v_t^2 + v_r^2)[/tex]

where v_t is tangential (original) speed and v_r is the radial speed immediately after the rocket fired.

Since the force of the rocket was entirely in the radial direction, was there any torque applied? What does that tell you about angular momentum?

b) Describe the subsequent motion of the satellite and plot T(r), V(r), U(r), and E(r) after the rocket fires.

Using the effective potential:

[tex]V_{eff}(r) + T(r) = E(r)[/tex] where

[tex]V_{eff}(r) = U(r) + \frac{L^2}{2mr^2}[/tex]

and the radial kinetic energy,

[tex]T(r) = \frac{1}{2}mv_r^2[/tex]

For circular orbit, T(r) = 0. Since T(r) is non-zero, what does this tell you about the kind of orbit? Does it have a constant radius?

AM
 
Thanks Andrew.
 

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