Jacob87411
Apr4-05, 02:31 PM
A diffraction pattern is produced on a screen 140 cm from a single slit using monochromatic light of wavelength 500 nm. The distance from the center of the central maximum to the first order maximum is 3 mm. Calculate the slit width (assume first order maximum is halfway between the first and second order minima).
So things we know-
From the slit to the screen is 140 cm
Wavelength = 500 nm
from the center of the central maximum to the first order is 3 mm.
if we use: Sin of the angle = (M * Wavelength)/d =
sin of the angle = (1 * 500x10^-7) / .003
That gives the angle of the central maximum which we can then plug into
sin angle=wavelength/slit width?
So things we know-
From the slit to the screen is 140 cm
Wavelength = 500 nm
from the center of the central maximum to the first order is 3 mm.
if we use: Sin of the angle = (M * Wavelength)/d =
sin of the angle = (1 * 500x10^-7) / .003
That gives the angle of the central maximum which we can then plug into
sin angle=wavelength/slit width?