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Raparicio
Apr7-05, 02:23 PM
Hello All,
I have a question about photons. In A. Einstein ecuation (about Lorenzt transformation), there's a square root of c^2-v^2. My question is about what is the v represented: a vector? Only one direction vector? Only his module?
best reggards.
R.apaparioscios.
Do you mean (1 - β^2)^1/2, where β = v/c? It's just the size of the velocity, so the modulus.
Raparicio
Apr7-05, 04:47 PM
Do you mean (1 - β^2)^1/2, where β = v/c? It's just the size of the velocity, so the modulus.
It's right. Is the modulus, but: could be a paravector???
What's a paravector? :confused:
Raparicio
Apr8-05, 12:57 PM
Hello now,
A paravector is a generalization of a vector, with a non-vectorial part and a vectorial part (like complex numbers have Real + Complex number). There are more generenalizations of vectors, like hypercomplex of hamilton, and the most general interesting now is Clifford Algebras and Geometric Algebra.
Could say that a vector is a paravector without escalar part in this example.
my best reggards.
dextercioby
Apr8-05, 01:06 PM
You'd need a new theory for that.For the Theory of Relativity developed over the last exactly 100 years,that "v" from \beta or \gamma is a scalar,namely \left|\vec{v}\right| ...That "v" has nothing to do with photons,of course...
Daniel.
Hello All,
I have a question about photons. In A. Einstein ecuation (about Lorenzt transformation), there's a square root of c^2-v^2. My question is about what is the v represented: a vector? Only one direction vector? Only his module?
best reggards.
R.apaparioscios.
the v is just an ordinary velocity-vector. It has three dimensions or equivalently it has three components, just like in the case of Lorentz transformations. That's all. The vē is the magnitude of this vector which is determined by calculating the scalar product of this vector with itself.
The v is the velocity of one frame of reference to another...
marlon
Raparicio
Apr9-05, 03:49 AM
the v is just an ordinary velocity-vector. It has three dimensions or equivalently it has three components, just like in the case of Lorentz transformations. That's all. The vē is the magnitude of this vector which is determined by calculating the scalar product of this vector with itself.
The v is the velocity of one frame of reference to another...
marlon
Could be the velocity, a paravector or multivector, and this 'v' its module???
dextercioby
Apr9-05, 08:49 AM
It could iff u changed the whole theory.It could be pseudovector,the trace of a rank 658 tensor,etc...
Daniel.
Raparicio
Apr9-05, 09:29 AM
It could iff u changed the whole theory.It could be pseudovector,the trace of a rank 658 tensor,etc...
Daniel.
Daniel,
What whole theory?
Maybe he means SR, I dunno.
dextercioby
Apr9-05, 09:52 AM
Yeah,change SR,you'll need to change GR as well.For the time being,they are successful theories and these theories address the velocity in the "gamma-factor" as the modulus of an ordinary 3-vector...
Daniel.
Raparicio
Apr9-05, 10:39 AM
Dear Daniel and forum,
Have you seen this:
http://www.physicsforums.com/showthread.php?t=69849
Is related about the present post.
best reggards.
Raparicio
Apr15-05, 02:51 PM
Yeah,change SR,you'll need to change GR as well.For the time being,they are successful theories and these theories address the velocity in the "gamma-factor" as the modulus of an ordinary 3-vector...
Daniel.
I'm sorry for my ignorance. What means SR and GR?
dextercioby
Apr15-05, 03:02 PM
Special Relativity and General Relativity.
Daniel.
Raparicio
Apr15-05, 03:06 PM
Special Relativity and General Relativity.
Daniel.
Dear Daniel,
What I say is, what to unify SR an GR, we need to think the same way in both, and Geometrical Algebra provides a new tools to face it. If we take a multivector and apply a generalization of the Bertrand Russell circle, there are very interesting insights.
But this is very confusing to me.
Thanks another time.
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