Find a vector c that bisects the angle

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Homework Help Overview

The discussion revolves around finding a vector that bisects the angle between two given vectors in three-dimensional space. The vectors in question are a = i + 5j - 2k and b = -3i + j + 6k. Participants explore the implications of vector addition and the geometric interpretation of the bisector in relation to a mirror setup for a laser beam.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the concept of vector addition in both 2D and 3D contexts, questioning whether the sum of two vectors can represent the bisector of the angle between them. There are inquiries about the implications of equal magnitudes of vectors and how this relates to the problem at hand.

Discussion Status

The discussion is ongoing, with participants sharing their thoughts and questioning assumptions about vector addition and its geometric interpretations. Some guidance has been offered regarding visualizing vectors and their resultant, but there is no explicit consensus on the correct approach to finding the bisector.

Contextual Notes

Participants mention constraints related to visualizing the problem and the specific application of the vectors in a laser beam scenario, which may affect their understanding of the geometric relationships involved.

particleaccelerater
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any help is appreciated

Find a vector c that bisects the angle between the vectors a = i + 5j - 2k andb = -3i + j + 6k.
 
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particle,

Could you find one if a and b had the same magnitude?
 
no i have never done anything like this but i can descirbe the scenario to you

this is for program iam writing for a laser beam. two arbitrary vectors represent the two distances from the laser to the mirror and from the mirror to a target. The bisector represents the normal of the plane(really the mirror). From that bisector, i will have to find the angles the mirror is being pivoted and rotated.

( i would much rather you demonstrate it on this example, i can understand it better by seeing the math, but not visually in my head) thanks for any help you can give me
 
particle,

"i would much rather you demonstrate it on this example, i can understand it better by seeing the math, but not visually in my head"

I'll get to this example when you're ready for it!

From a single point, draw two different vectors with equal magnitudes. Now draw their sum. Does that help?
 
i can add vectors in 2d ut not 3d
 
It's precisely the same thing, particleaccelerator. Put the vectors tail-to-head and draw the resultant line. Or, analytically, just add the components.

- Warren
 
is it -2i + 6j + 4k? just add the components?
 
particleaccelerater said:
is it -2i + 6j + 4k? just add the components?
Yeap. That is the sum of the two vectors.

The Bob (2004 ©)
 
will someone just do this example for me so ican understand it, icant see it visually very well
 
  • #10
so the sum of two vectors is the bisector of the angle between the vectors?
 
  • #11
particleaccelerater said:
so the sum of two vectors is the bisector of the angle between the vectors?
Might be. Let me think in 3D first.

The Bob (2004 ©)
 
  • #12
I believe it would give you the direction of the bisector.

The Bob (2004 ©)
 
  • #13
assuming a plane to be a mirror and two vectors coming from the same point on the plane where the point represents the point of reflection on the mirror, does the resultant of these two vectors represent the normal of the plane(mirror). i am trying to figure this out because given the coordinates of where the target should be, i have to pivot the mirror horizantally and vertically to make this happen
 
  • #14
particle,

You said you can add vectors in 2d. Try it with 2 vectors of equal magnitude (length) and then with two vectors of different magnitude. See if that answers your question:"so the sum of two vectors is the bisector of the angle between the vectors?"
 
  • #15
assuming a plane to be a mirror and two vectors coming from the same point on the plane where the point represents the point of reflection on the mirror, does the resultant of these two vectors represent the normal of the plane(mirror). i am trying to figure this out because given the coordinates of where the target should be, i have to pivot the mirror horizantally and vertically to make this happen
 
  • #16
particle,

Ok, I give up! You don't want to learn anything; you just want somebody to do your work for you. If you wait around long enough somebody probably will. But it won't be me.

Good luck!
 
  • #17
all i want is for somebody to tell me if my thinking is right

assuming a plane to be a mirror and two vectors coming from the same point on the plane where the point represents the point of reflection on the mirror, does the resultant of these two vectors represent the normal of the plane(mirror)?

i am trying to figure this out because given the coordinates of where the target should be, i have to pivot the mirror horizantally and vertically to make this happen
 
  • #18
I empathsis with jdavel but I am going to see what I can do for particles understanding.

First off, http://descartes.cnice.mecd.es/ingles/Bach_CNST_1/Analytical_geometry/Geometria_8-1.htm might help.

See if that helps. I need to think of a way of describing what you need to do.

The Bob (2004 ©)
 
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  • #19
Right. I have had a think and here is what I have come up with. This example is in 2D.

Find two points at the end of the vectors in the same way you use co-ordinate for normal equations of y and x.

Use this points to find the mid-point of the line that would join them e.g:

[tex](\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2})[/tex]

Then use this and the origin to find the equation of the line with the second general equation e.g. y1 - y2 = m(x1 - x2).

See if it can be applied to 3D and you are away.

The Bob (2004 ©)
 

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