Max/Min Values for f(x,y,z): Lagrange Multipliers

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SUMMARY

The discussion focuses on finding the maximum and minimum values of the function f(x,y,z) = 3x - y - 3z under the constraints x + y - z = 0 and x² + 2z² = 1 using Lagrange multipliers. The Lagrange function is defined as F(x,y,z) = 3x - y - 3z + λ₁(x + y - z) + λ₂(x² + 2z² - 1). Participants are advised to compute the partial derivatives and set them to zero to solve for critical points, although the nature of these points (maxima or minima) remains uncertain.

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Greetings all,

Find the max and min values of
f(x,y.z)=3x-y-3z
subject to
x+y-z=0, x^(2)+2z^(2)=1

can anybody help me get this problem started.

thanks
 
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Just write the Lagrange function of the problem:

[tex]F(x,y,z)=3x-y-3z+\lambda_1(x+y-z)+\lambda_2(x^{2}+2z^{2}-1)[/tex]

Then find the partial derivatives (they have to be 0), and solve the system of equations.
 
You'll find the critical points,though...You can't be sure which is a mex & which is a min...

Daniel.
 

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