How Far Will Jill Run to Catch the Cart?

[stangeroo]

Jill has just gotten out of her car in the grocery store parking lot. The parking lot is on a hill and is tilted 3 degrees. Fifty meters downhill from Jill, a little old lady let's go of a fully loaded shopping cart. The cart, with frictionless wheels, starts to roll straight downhill. Jill immediately starts to sprint after the cart with her top acceleration of 2 m/s^2

How far has the cart rolled before jill catches it?

I know you need to set two formulas equal to each other, but I don't know which formulas

EDIT: I started off by drawing it out and taking the sin of 3 degrees, .0523 and multiplying it by 9.8 to get the acceleration of the cart, I don't know where to go from there

 

[stangeroo]

bump, anyone

 

[marlon]

the cart's acceleration is NOT 9.81 but 9.81sin(3°)

Jill's initial position and velocity is ZERO, her acceleration is 2 + 9.81sin(3°) due to gravity also.

For the cart : initial velocity is zero; initial position is 50 (i assume the 50m downward is along the hill and not measured horizontally)...This is all you need

Use x = x_0 + v_0*t + 1/2at²

where x_0 is initial position and v_0 is initial velocity
marlon