How Fast is the Area of an Equilateral Triangle Changing?

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SUMMARY

The discussion focuses on calculating the rate of change of the area of an equilateral triangle as its height increases. The height (h) is increasing at a rate of 3 cm/min, and the area (A) is expressed as a function of height. By applying the chain rule, the formula for the rate of change of area, dA/dt, is established as dA/dt = (dA/dh) * (dh/dt). The specific values for height and area are also addressed, with h set at 5 cm.

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  • Knowledge of the formula for the area of an equilateral triangle
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I need help with the question: The height h of an equilateral triangle is increasing at a rate of 3cm/min. How fast is the area changing when h is 5 cm.
 
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What's the area?What's the height?Can u write the former as a function of the latter?

Daniel.
 
You want [itex]dA/dt[/itex]. Use the chain rule:

[tex]\frac{dA}{dt} = \frac{dA}{dh} \frac{dh}{dt}[/tex]

Of course, you'll need to work out what the two derivatives on the right are.
 

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