What Are the Correct Equations for Solving Magnetism Problems?

  • Thread starter Thread starter shikagami
  • Start date Start date
  • Tags Tags
    Magnetism
Click For Summary

Homework Help Overview

The discussion revolves around solving a magnetism problem involving a singly charged Li^7 ion accelerated through a potential difference and moving in a magnetic field. Participants are exploring the appropriate equations to determine the radius of the ion's path in the magnetic field.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use two different equations to find the radius of the ion's path, leading to significantly different results. Some participants question the validity of the equations used, particularly the application of V=(kq)/r in this context.

Discussion Status

The discussion is ongoing, with participants questioning the assumptions behind the equations and their applicability to the problem. There is no explicit consensus on which solution is correct, and some guidance has been offered regarding the misapplication of certain formulas.

Contextual Notes

Participants are navigating the complexities of using equations from different contexts, with confusion surrounding the definitions and applications of voltage and radius in relation to magnetic fields.

shikagami
Messages
42
Reaction score
0
I'm confused if I am using the right equations to solve this problem.

P: A singly charged Li^7 ion has a mass of 1.16x10^-26kg. It is accelerated through a potential difference of 500 Volts and then enters a magnetic field of 0.4 Teslas, moving perpendicular to the field. What is the radius of its path in the magnetic field.


I had two different solutions to this problem that has to completely different answers. First, I figured I can use the equation V=(kq)/r. Then I solved for the radius. The second way is by using the volts equation: V=PE/q, which I use to solve for the potential energy. I then used this in the kinetic energy equation KE=1/2mv^2 to solve for the velocity. This velocity I then used in the equation r=(mV)/(Bq). I got 2.88x10^-12 meters for the first solution and 3.44x10^13 meters for the second solution. Which one is right is any?
 
Physics news on Phys.org
What is your understanding of V=(kq)/r? How did you use it?
 
Well... since I knew how much volts there is, I figured that it is faster to just use that formula where k is the Coulomb constant (8.99x10^9 Nm^2/C^2), then just solve for the radius. Is it possible to use this equation like that?
 
shikagami said:
Well... since I knew how much volts there is, I figured that it is faster to just use that formula where k is the Coulomb constant (8.99x10^9 Nm^2/C^2), then just solve for the radius. Is it possible to use this equation like that?

No. The r in that equation is distance from a charge q and the V is is the electric potential due to that charge. It has nothing to do with the radius of curvature of a path of a particle, and that V is for a completely dirrerent geometry than what you have.
 
So is my second solution the right one? or are they both wrong?
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
11
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
12
Views
2K