Solve x+y=5 & x^x+y^y=31 | Get Help Here

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  • Thread starter Thread starter abia ubong
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Discussion Overview

The discussion revolves around solving a system of equations: x + y = 5 and x^x + y^y = 31. Participants seek assistance in finding solutions to these simultaneous equations, which involve both algebraic and potentially transcendental elements.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant requests help with the equations, indicating they are simultaneous.
  • Another participant suggests that (2, 3) is a solution, expressing familiarity with the problem.
  • A different participant expresses urgency for a solution, emphasizing their need for assistance.
  • One participant reiterates a previous response, reformulating the second equation using y = 5 - x and notes that it cannot be solved using elementary functions. They mention the possibility of using the Lambert W function for such equations.
  • This participant also states that (3, 2) and (2, 3) are solutions, suggesting they are likely the only solutions and that verification should be straightforward.

Areas of Agreement / Disagreement

There appears to be some agreement on the specific solutions (2, 3) and (3, 2) being valid, but the method of solving the second equation remains contested, with differing opinions on the feasibility of finding a general solution.

Contextual Notes

The discussion highlights the complexity of solving the second equation and the limitations of elementary functions in this context. The mention of the Lambert W function introduces additional considerations that are not fully resolved.

abia ubong
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hey i need help with this its a simul eqn ,here it is ,
x+y=5,x^x+y^y=31.any help will be appreciated
 
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abia ubong said:
hey i need help with this its a simul eqn ,here it is ,
x+y=5,x^x+y^y=31.any help will be appreciated
Why do I feel I have seen this before? :rolleyes:

(2,3)

The Bob (2004 ©)
 
can i get a solution plssssssssssssssss
 
This is, after all, the second time you have posted this question: all I can do is give the same answer I did before: from x+ y= 5, y= 5- x so the second equation can be written xx+ (5-x)5-x= 31. That equation cannot be solved (for arbitrary right hand side) by any elementary functions. It is possible that such an equation can be solved by the "Lambert W function".

However, as was explained the last time this was posted, in this particular problem,
33+ 22= 31 so x= 3, y= 2 and x= 2, y= 3 are solutions. They are probably the only solutions. It shouldn't be too difficult to check that.
 

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