whats the answer to dis one???helppppppppppppp!!!

[pokipok]

3log_6 - log_6 12 + log_6 2 = ???? (the base is 6)





whats the vertical asymptote, x-intercept, range and domain for this one -
log_x 4

[CRGreathouse]

Use the basic properties of logarithms:

log_b(xy) = log_b(x) + log_b(y)
log_b(x^y) = y log_b(x)
log_b(x/y) = log_b(x) - log_b(y)

[dextercioby]

As for the second,use

\log_{4}x=\frac{\ln x}{\ln 4}

Daniel.

[pokipok]

As for the second,use

\log_{4}x=\frac{\ln x}{\ln 4}

Daniel.


how did u get dat?
logx4 = In x/In 4??

[HallsofIvy]

Saying "y= log4 x" is the same as saying "x= 4y". Now take the logarithm (with whatever base you want- log10 or ln if you want to use a calculator): log x= log 4[sup]y[/sup= y log 4 so y= log x/log 4.

[pokipok]

Saying "y= log4 x" is the same as saying "x= 4y". Now take the logarithm (with whatever base you want- log10 or ln if you want to use a calculator): log x= log 4[sup]y[/sup= y log 4 so y= log x/log 4.



x is the base not 4, logx4,, how oh how do u?

[HallsofIvy]

What do you want to do with logx 4? If you x is a given number, then you would find log[sub]x[sub]4, just as before: (log 4)/(log x). Again, the log can be either base 10 or natural log whichever is easier.

[pokipok]

What do you want to do with logx 4? If you x is a given number, then you would find log[sub]x[sub]4, just as before: (log 4)/(log x). Again, the log can be either base 10 or natural log whichever is easier.



find the domain, range ang x-intercept y=logx4