Find Volume of Metal Object: 860-785 N, 9.8 m/s^2

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SUMMARY

The volume of a metal object can be calculated using Archimedes' principle and the buoyant force. In this case, a spring scale reads 860 N in air and 785 N when submerged in water, indicating a buoyant force of 75 N. Using the formula Fb = ρVg, where ρ is the density of water (1000 kg/m³) and g is the acceleration due to gravity (9.8 m/s²), the volume is determined to be 0.00765 m³.

PREREQUISITES
  • Understanding of Archimedes' principle
  • Knowledge of buoyant force calculations
  • Familiarity with the formula Fb = ρVg
  • Basic grasp of units of measurement in physics (N, m³, kg/m³)
NEXT STEPS
  • Study the applications of Archimedes' principle in fluid mechanics
  • Explore the concept of buoyancy in different fluids
  • Learn about the effects of temperature on water density
  • Investigate the relationship between weight and volume in various materials
USEFUL FOR

Physics students, engineers, and anyone interested in fluid dynamics and buoyancy calculations will benefit from this discussion.

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A metal object is suspended from a spring scale. The scale reads 860 N when the object is suspended in air, and 785 N when the object is completely submerged in water.
The acceleration due to gravity is 9.8 m/s^2.
Find the volume of the object. Answer in m^3.
 
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To find the volume of the metal object, we can use the principle of buoyancy. The difference in the scale readings (860 N - 785 N = 75 N) represents the buoyant force acting on the object when it is submerged in water. This buoyant force is equal to the weight of the water displaced by the object.

We can use the formula Fb = ρVg, where Fb is the buoyant force, ρ is the density of water (1000 kg/m^3), V is the volume of the object, and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values, we get 75 N = (1000 kg/m^3) V (9.8 m/s^2).

Solving for V, we get V = 0.00765 m^3.

Therefore, the volume of the metal object is 0.00765 m^3.
 

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