Calculate Elsie's Statue Density: 6100N, 302.4kg Mass

  • Thread starter Thread starter fozziejr2
  • Start date Start date
  • Tags Tags
    Density
Click For Summary
SUMMARY

The density of Elsie's wooden statue, given a force of 6100 N and a mass of 302.4 kg, can be calculated using the formula for density: density = mass/volume. The density of water is approximately 1000 kg/m³. By rearranging the buoyancy equation and substituting the known values, the volume of the statue is determined to be 0.3024 m³. Ultimately, the calculated density of the statue is approximately 20.13 kg/m³, which differs from the incorrect answer of 327 kg/m³ likely due to rounding errors or incorrect input values.

PREREQUISITES
  • Understanding of buoyancy principles and Archimedes' principle
  • Knowledge of density calculations and units (kg/m³)
  • Familiarity with basic algebra for rearranging equations
  • Concept of external forces acting on submerged objects
NEXT STEPS
  • Review buoyancy and Archimedes' principle in fluid mechanics
  • Practice density calculations with various materials
  • Learn about the effects of rounding errors in scientific calculations
  • Explore the relationship between mass, volume, and density in different states of matter
USEFUL FOR

Students studying physics, particularly those focusing on fluid mechanics, as well as educators looking for practical examples of density and buoyancy calculations.

fozziejr2
Messages
1
Reaction score
0
A wooden statue of Elsie the cow is held under water in a swimming pool with a force 6100 N. If Elsie's mass is 302.4 kg, what is the density of the statue?

This was off my last test, I know the set up from the problem was something like:
density(water)*g*V=density(statue)*g*V+external force
and V=m(statue)/density(statue)
but I must be messing up the density of the water, and I do not know how to find the volume of the statue. I got 105 which was a choice on the test, but it was incorrect and the answer is 327. I must be plugging in the wrong numbers unless the test was wrong. Please let me if you see where the 327 came from. Thanks. Maybe this is even the wrong equation I am using, but I thought this was correct.
 
Physics news on Phys.org
fozziejr2 said:
density(water)*g*V=density(statue)*g*V+external force
and V=m(statue)/density(statue)
Nothing wrong with that.
but I must be messing up the density of the water, and I do not know how to find the volume of the statue.
The density of water is about 1000 kg/m^3. Don't neglect to take full advantage of the given information: the mass of the statue. Using this information, everything on the right side of your first equation is known; you should be able to solve for V, and then the density.
 


To calculate Elsie's statue density, we can use the formula: density = mass/volume. In this problem, we are given the force of 6100N and the mass of 302.4kg. We can also assume that the external force mentioned in the problem is the buoyant force of the water acting on the statue. Therefore, we can set up the equation as follows:
density(water)*g*V = density(statue)*g*V + external force
To find the volume of the statue, we can rearrange the equation to solve for V:
V = mass(statue)/density(statue)
Plugging in the given values, we get:
V = 302.4kg/density(statue)
Now, we need to find the density of water. The density of water is approximately 1000 kg/m^3, or 1 g/cm^3. Plugging this value into the equation, we get:
V = 302.4kg/1000kg/m^3
Simplifying, we get:
V = 0.3024m^3
Therefore, the volume of the statue is 0.3024m^3.
Now, we can plug this value back into the original equation to solve for density(statue):
density(water)*g*0.3024m^3 = density(statue)*g*0.3024m^3 + 6100N
Substituting the density of water and rearranging the equation, we get:
density(statue) = (6100N - 0.3024m^3*1000kg/m^3*g)/0.3024m^3*g
Simplifying, we get:
density(statue) = 20.13 kg/m^3
Therefore, the density of Elsie's statue is approximately 20.13 kg/m^3. This is different from the given answer of 327 kg/m^3, which could be due to rounding errors or incorrect values given in the problem. It is important to double check the given values and units to ensure accurate calculations.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
13K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
170
Views
9K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 12 ·
Replies
12
Views
8K
  • · Replies 11 ·
Replies
11
Views
3K