Calculate the charge on plate Capacitor

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Homework Help Overview

The discussion revolves around calculating the charge on capacitor plates in a circuit involving multiple capacitors with given capacitance values. The original poster attempts to determine the charge on specific plates based on provided charges and capacitance values, but encounters discrepancies with the expected answers.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of calculating charge using the formula Q = VC, with attempts to apply it to different capacitor configurations. Questions arise regarding the accuracy of calculations and the potential for rounding errors affecting results.

Discussion Status

Some participants express uncertainty about their calculations and seek validation of their methods. There is acknowledgment that the original poster's approach appears correct, but confusion remains regarding the computer's feedback on their answers. Guidance is offered regarding the possibility of input format issues affecting the correctness of the submitted answers.

Contextual Notes

Participants note that the problem may involve rigid formatting requirements for answers when submitted to a computer program, which could lead to correct calculations being marked as incorrect.

eutopia
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this problem probably took me a whole hour :mad: but it seems like i don't know what I'm doing wrong...

diagram: http://loncapa.elps.k12.mi.us/cgi-bin/plot.gif?file=MaMargaret_elps_1115513252_23407965_plot.data&output=png

Capacitor MR=78.9 nF
Capacitor PL=38.3 nF
Capacitor TN=35.3 nF
Capacitor US=38.5 nF

Calculate the charge on plate S, if the charge on plate L is 6.51e-8 C. (right) Answer: 9.72e-8 C

Calculate the charge on plate R, if the charge on plate N is 7.29e-8 C.
(wrong) answer: 5.324771655e-8 C:

For the first part, I did

[tex]{Q} = {V}{C}[/tex]

[tex]{Q} = 6.51e-8[/tex]

[tex]{C} = [ 78.9/(78.9+38.3) ] times 38.3e-9 = 2.578e-8[/tex]

[tex]{V} = Q/C = 2.5348[/tex]

the second charge would then be: [tex]{Q} = (38.5e-9)(2.5348)[/tex]

For the second part, I used the same process and got 5.324771655e-8 Columbs but it seems to be wrong, at least the computer says it's wrong, and I can't figure out what's wrong:


[tex]{Q} = 7.29e-8[/tex]

[tex]{C} = 35.3e-9[/tex]

[tex]{V} = (7.29e-8)/(35.5e-9) = 2.0651558[/tex]

-------------------

[tex]{V} = [ 38.3/(78.9+38.3) ] (2.0651558) = .6748760019[/tex]

[tex]{C} = 78.9e-9[/tex]

[tex]{Q} = 5.32477e-8[/tex]
 
Last edited by a moderator:
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eutopia said:
Capacitor MR=78.9 nF
Capacitor PL=38.3 nF
Capacitor TN=35.3 nF
Capacitor US=38.5 nF

Calculate the charge on plate R, if the charge on plate N is 7.29e-8 C.
(wrong) answer: 5.324771655e-8 C:

For the second part, I used the same process and got 5.324771655e-8 Columbs but it seems to be wrong, at least the computer says it's wrong, and I can't figure out what's wrong:
Your method is correct. But I get 5.34 e-8 C.:

Q/C = V

So V = 7.29e-8 /3.53 e-8 = 2.07 Volts.

[tex]C_{ML} = C_{MR}C_{PL}/(C_{PL}+C_{MR}) = 78.9 * 38.3/(78.9 + 38.3) = 2.58 e-8[/tex] (as you found)

So Q = VC = 2.07 x 2.58 e-8 C. = 5.34 e-8 C.

AM
 
i guess i just kept all the decimals in there... i'll check it again.


*Arg... it's still not right. If i round it becomes 5.34, if I don't it's 5.32
 
Last edited:
im so clueless...
 
Am I doing it right? If I am, then I'm leaving the problem and moving on. If I'm not, then I'll try some more; but I don't want to dwell on something that I absolutely can't figure out what's wrong with... and turns out nothing was wrong. If something WAS wrong then I wouldn't mind thinking about it more
 
please tell me I'm doing it right...
 
eutopia said:
please tell me I'm doing it right...
Eutopia: I already said your method was correct. That means you have it right.

AM
 
Your work looks fine. You said it was given as incorrect by the computer, so it is possible that the problem is in how you are entering the solution. Sometimes computer programs are rigid in how they want the solution entered, so even if it is a correct solution, if it isn't written the exact way it expects, the answer is marked incorrect.
 

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