Is Intuition Enough to Determine Asymptotes in Calculus?

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SUMMARY

The discussion centers on evaluating the limit of the function \( f(x) = \frac{4}{x^2} - x \) as \( x \) approaches infinity and determining its asymptotic behavior. The function approaches negative infinity as \( x \) approaches infinity, indicating no horizontal asymptote exists. Additionally, the function has a vertical asymptote at \( x = 0 \), as \( f(x) \) approaches infinity from both sides when \( x \) approaches zero. The participants emphasize the importance of rigorous methods over intuition when determining asymptotes in calculus.

PREREQUISITES
  • Understanding of limits in calculus
  • Knowledge of horizontal and vertical asymptotes
  • Familiarity with rational functions
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the concept of limits at infinity in calculus
  • Learn how to identify horizontal and vertical asymptotes for rational functions
  • Explore the use of L'Hôpital's Rule for limit evaluation
  • Practice graphing rational functions to visualize asymptotic behavior
USEFUL FOR

Students preparing for calculus exams, educators teaching asymptotic analysis, and anyone seeking to deepen their understanding of limits and asymptotes in mathematical functions.

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I am preparing to study for my exam, and there is something I am not sure about when evaluating the limit x --> Infinity of 4/x^2 - x
Intuitively the function seems to go to minus infinity, and I wonder if that is a sufficient answer or am I overlooking a rigorous method that should be applied here. It doesn't seem sufficient because I am looking for a horizontal asymptote and this answer doesn't guide me to a definitive point where one exists although it implies there would be one. Can someone give me a clue as to the method that would get me a clear answer.

Also as this function goes to 0, 4/0 is not defined so that's all I need to establish, right? And this would imply a vertical asymptote is at x = 0 which in turn implies that the function approaches infinity from above and below?
 
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Yes, what you have said is correct. You might prefer to write this as a single
fraction: (4-x3)/x2 which has a vertical asymptote at x= 0, goes to negative infinity as x goes to infinity, and goes to infinity as x goes to negative infinity.
 
So I can be certain at this point that there is horizontal asymptote.

I haven't looked at the graph I am trying to make certain that I can be confident in what I know from the equation without looking at the graph, as I would like to be in an exam.

I will be getting to looking at graphs to check my work next, believe it or not there is method to my madness.
 

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