Calculating Properties of Helium Gas Under Isothermal Compression

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SUMMARY

The discussion focuses on calculating properties of a 2.00 mol sample of helium gas undergoing isothermal compression from 0.400 atm to 1.20 atm at a constant temperature of 300K. The ideal gas law (PV=nRT) is identified as the primary formula for these calculations, with emphasis on Boyle's Law for isothermal processes. The work done on the gas is determined to be equal to the heat transferred, as there is no change in internal energy during isothermal compression. The work is calculated using a natural logarithmic function based on the change in volume.

PREREQUISITES
  • Understanding of the ideal gas law (PV=nRT)
  • Familiarity with Boyle's Law for isothermal processes
  • Knowledge of natural logarithmic functions
  • Basic thermodynamics concepts, particularly regarding internal energy
NEXT STEPS
  • Calculate the volume of gas using the ideal gas law for isothermal conditions
  • Determine the work done on the gas during isothermal compression
  • Explore the relationship between work and heat transfer in isothermal processes
  • Investigate real-world applications of the ideal gas law in engineering scenarios
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Students and professionals in physics and engineering, particularly those studying thermodynamics and gas laws, will benefit from this discussion.

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a 2.00 mol sample of helium gas at 300K and 0.400atm pressure is compressed isothermally to 1.20atm
Find the volume of the gas, work done on the gas and the energy transferred by heat

just wondering how to approach this question, and what formulae i hould use where?
 
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The formula to use is the one most obvious formula: the ideal gas law formula. It has three variation, called Charles' Law, Boyle' Law and Gaye-Lusac's Law, but I recommend sticking with the ideal gas formula. (Starts with "PV," remember?)

In an isothermal compression, the temperature stays the same, so there is no change in internal energy, therfore, the work on the gas must equal the heat given off by the gas.

Since ideal isothermal processes are hyperbolic, the work done must be a "natural log" function of the change in volume. You have probably seen only one natural log function so far, am I right?
 
thankyou for your help
 

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