gigi9
Oct20-03, 09:56 PM
Plz help me out w/ the problem below. Thanks.
Find the length of the specified arc of the given curve:
y=1/3sqrt(x)*(3-x), 0<=x <=3
Formular to find arc length is integral from a to b of sqrt(1+f'(x)^2)dx
I got to these steps below and not sure exactly wat to do next
***y'=1/6x^(-1/2)(3-3x)=1/2x^(-1/2)(1-x)
***V= integral from 0 to 3 of sqrt{1+[1/2x^(-1/2)*(1-x)])2} dx
=integral 0 to 3 of sqrt[1/2+1/4*x^-1+1/4*x] dx
Find the length of the specified arc of the given curve:
y=1/3sqrt(x)*(3-x), 0<=x <=3
Formular to find arc length is integral from a to b of sqrt(1+f'(x)^2)dx
I got to these steps below and not sure exactly wat to do next
***y'=1/6x^(-1/2)(3-3x)=1/2x^(-1/2)(1-x)
***V= integral from 0 to 3 of sqrt{1+[1/2x^(-1/2)*(1-x)])2} dx
=integral 0 to 3 of sqrt[1/2+1/4*x^-1+1/4*x] dx