How Many Choice Functions Exist for Finite and Infinite Sets?

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SUMMARY

In the discussion regarding choice functions for finite and infinite sets, it is established that if |X| = n > 0, the number of choice functions from the power set of X minus the empty set, denoted as P(X)\{{}}, to X, is given by the product 1C1nC12C1nC2...nC1nCn. The complexity increases significantly when dealing with infinite sets, particularly due to the implications of the axiom of choice, which can lead to scenarios where no choice functions exist. A choice function on a set S is defined as a function f: S → US, where f(x) is an element of x, representing a selection from each subset in S.

PREREQUISITES
  • Understanding of set theory and cardinality
  • Familiarity with the concept of choice functions
  • Knowledge of the axiom of choice in mathematics
  • Basic comprehension of Cartesian products
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Mathematicians, students of advanced set theory, and anyone interested in the foundational principles of choice functions and their implications in both finite and infinite contexts.

honestrosewater
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If |X| = n > 0, there are 1C1nC12C1nC2...nC1nCn many choice functions from (power set of X minus empty set) P(X)\{{}} to X?
Just curious. I'm jumping ahead a bit, but that makes sense to me. Is it correct? Is it much more difficult to understand when X is infinite?
 
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Sounds right.

Infinite sets make things more interesting! For instance, there might be 0 choice functions, if you deny the axiom of choice! Though, if there's at least one choice function on a set S, and S has an element with cardinality a, then there must be at least a choice functions.

By a "choice function on S", I mean a function f:S --> US such that f(x) is in x. Or, equivalently, an element in the cartesian product of all the elements of S.
 

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