Is this the general solution for the DE y''+4y' +20y=0 with initial conditions?

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The general solution for the differential equation y'' + 4y' + 20y = 0 with initial conditions y(0) = -3 and y'(0) = 5 is e^{-2t}(C_1 cos(4t) + C_2 sin(4t)). The discussion confirms that while this represents the general solution, the particular solution is what is ultimately required for the given initial conditions. Daniel affirms the correctness of this conclusion.

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RadiationX
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solve [tex]y''+4y' +20y=0 ;y(0)=-3 ,\\ y'(0)=5[/tex] is this the general solution?

[tex]e^{-2t}(C_1\cos{4t} + C_2\sin{4t})[/tex]
 
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Yes. It is.
 
You don't need the general solution as the final answer,but the particular solution.

Daniel.
 

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