another calc. question to check!

[laker_gurl3]

Find the area bounded by y=sin(x) and y= x(pi)/12

the final answer i got was A= 1.969

Can anyone please confirm this?

[OlderDan]

If that second function is y = x*pi/12 it is not correct

[laker_gurl3]

yeah..that's the second function..
well im checking it over again, im not sure how else i can do it

[laker_gurl3]

just to make sure, another way to write the second function is , (X/12) multiplied by pi

[OlderDan]

just to make sure, another way to write the second function is , (X/12) multiplied by pi

That is correct. And you are trying to find the area bounded by the two functions. What integral are you doing, including the limits you are using?

[laker_gurl3]

i am using 2.446 and 0

2.446 2.446
| |
| sin (x) - | (x/12) multipled by pi
| |
0 0

[OlderDan]

Those are the correct limits. The correct answer is less than 1. Are you using a calculator function to integrate, or doing it by hand?

[laker_gurl3]

Well, the first part of the answer i got was .9845.. Then i multiplied by 2 to get the area of the other side... does that sound good?

[OlderDan]

Well, the first part of the answer i got was .9845.. Then i multiplied by 2 to get the area of the other side... does that sound good?

OK sorry. I assumed you were talking about one side. My mistake.

You should have said your limts were from -2.446 to +2.446 with positive areas