Solving Physics Problem: Find Coefficient of Friction

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Homework Help Overview

The discussion revolves around calculating the coefficient of friction and understanding the forces acting on blocks in static and dynamic scenarios. The original poster presents two problems involving blocks resting on horizontal surfaces and the forces applied to them.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the maximum static friction force and the actual friction force acting on a block under an external force. They express confusion regarding the coefficient of friction in a second scenario where a block moves at constant velocity.

Discussion Status

Participants are engaging in clarifying concepts related to static friction and equilibrium. Some have pointed out errors in the original poster's reasoning, particularly regarding the conditions for equilibrium and the interpretation of friction forces. There is an ongoing exploration of the relationship between applied forces and friction.

Contextual Notes

Participants are discussing the implications of static friction and the conditions under which the actual frictional force can vary. The original poster expresses uncertainty about the validity of their calculations and the range of possible values for the coefficient of friction.

Eiano
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Hello all,
I'm new to this site and think it's a great idea to have a Physics site to help with, b/c we all know physics is the devil... (j/k) :)

Anyway I have this problem which I think i figured out but want to be sure.



Suppose a block of mass 25 kg rests on a horizontal surface and the coefficient of static friction is .22

a). What is the maximum possible Fs that could act on the block.

This is what I got, Fs=m*g*Us
x=(25)(10)(.22) = 55N

b). What is the avtual Fs that acts on the block if an external force of 25N acts horizontally on the block.

ME:
55-25= 30M


And this problem:

2). A 5kg block rests on a horizontal plane a force of 10N applied horizontally causes the block to more horizontally at a constant velocity. What is the coefficient of friction b/w the block and the plane, assume G is 9.8 m/s^2.

My answer doesn't make sense because the coefficient is not between 0 and 1.0 :rolleyes:

Anyway:

ME:
(9.8)(5)/10= about 5

Any ideas?

Thanks in advance!
 
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For 1b) the block is not moving. What must be true of the sum of the forces acting on the block?

#2 is upside down.
 
Last edited:
Okay, so for 1b.)

since it's at equilibrium, the sum of the forces must be equal. (err, must equal 0)?

Fs= (uS)(N)?
Fs= (.22)(25)
Fs=5.5?

Is this good or am I still missing something.

and thanks for correcting my error on 2. :blushing:
 
Last edited:
Eiano said:
Okay, so for 1b.)

since it's at equilibrium, the sum of the forces must be equal. (err, must equal 0)?

Fs= (uS)(N)?
Fs= (.22)(25)
Fs=5.5?

Is this good or am I still missing something.

and thanks for correcting my error on 2. :blushing:

The coefficient of static friction tells you the maximum possible force of friction acting on a stationary object. The actual frictional force can be any value between zero and the maximum. It is often less than the maximum, and that is true in this case.
 
OlderDan said:
The coefficient of static friction tells you the maximum possible force of friction acting on a stationary object. The actual frictional force can be any value between zero and the maximum. It is often less than the maximum, and that is true in this case.

thanks, i read the book and didn't get this concept, thanks again for clearing it up.
 

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