Calculating Centripetal Force with Law of Dynamics

Click For Summary
SUMMARY

The discussion focuses on calculating the gravitational force exerted by Jupiter on the Sun using Newton's law of universal gravitation, represented by the formula F = GMm/R². The calculated gravitational force is approximately 4.17e33 Newtons. Additionally, the centripetal force acting on Jupiter due to its orbit around the Sun is highlighted, indicating that gravitational attraction serves as a centripetal force. The need to determine the average distance between Jupiter and the Sun for accurate calculations is emphasized.

PREREQUISITES
  • Newton's law of universal gravitation
  • Centripetal force concepts
  • Basic understanding of celestial mechanics
  • Mathematical manipulation of physical formulas
NEXT STEPS
  • Study the derivation and application of Newton's law of universal gravitation
  • Learn about centripetal acceleration and its relation to orbital motion
  • Explore the calculation of average distances between celestial bodies
  • Investigate the implications of gravitational forces in multi-body systems
USEFUL FOR

Astronomy students, physics enthusiasts, and anyone interested in understanding gravitational forces and orbital dynamics in celestial mechanics.

bigman8424
Messages
25
Reaction score
0
anyone want to check my work, i would greatly appreciate it:

the quest. asks you to find law of mass attraction to calculate force of gravational of Jupiter towards sun:
used formula:

F = GMm/R2 = (6.67e-11)(1.99e30)(1.90e27)/(7.78e6)2
FJupiter = 4.17e33 Newtons ??

Then it asks centripetal force towards sun using law of dynamics??
 
Physics news on Phys.org
Gravity attraction force IS a centripetal force.

You may want to check the distance (in "m") (actually the average between the major & the minor semiaxis) between the 2 celestial bodies.

Daniel.
 
bigman8424 said:
...using law of dynamics??

this may suggest having to use [itex]a_{n} = \frac{v^2}{r}[/itex] to get acceleration, but you would need the velocity and the mass (to get the force from [itex]F = ma[/itex])
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
16
Views
2K
Replies
44
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
17
Views
3K
Replies
19
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
43
Views
5K