Quick Vx & Vy Problem: Get Help Now!

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SUMMARY

The discussion focuses on solving a physics problem involving horizontal and vertical velocities (Vx and Vy) related to an object falling. The horizontal velocity is confirmed as 2.75 m/s, and the object falls for 0.65 seconds under the influence of gravity at 9.8 m/s². The user incorrectly identified a distance of 2.07m as Vx, while the correct horizontal distance is approximately 1.79m. The calculations emphasize the importance of understanding the dimensions and relationships between Vx, Vy, and the time of fall.

PREREQUISITES
  • Understanding of basic physics concepts, particularly projectile motion.
  • Familiarity with kinematic equations for motion under gravity.
  • Ability to perform calculations involving horizontal and vertical components of motion.
  • Knowledge of units of measurement in physics (meters, seconds).
NEXT STEPS
  • Study kinematic equations for projectile motion in detail.
  • Learn how to calculate horizontal and vertical distances in free fall scenarios.
  • Explore the concept of acceleration due to gravity and its effects on falling objects.
  • Practice solving similar physics problems involving Vx and Vy calculations.
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone interested in understanding the dynamics of falling objects and their velocities.

samemikejones
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please help quick Vx and Vy prob

Thanks for the help everyone.
 
Last edited:
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2.07m is not Vx. It does not even have the correct dimensions. How did you get that? The horizontal distance where the book strikes the floor is numerically close to your 1.79 that you are calling Vy. What are the dimensions of that number? I don't see a Vy anywhere in your results.
 
Last edited:
It says the horizontal velocity is 2.75 m/s, and it hit the ground after 0.65 seconds. Simple work to find how far it went.

Then you know it is accelerating downwards at 9.8m/s^2 for the 0.65 seconds that it is falling, so how far does it fall?
 

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