Solving Limit of $\log {(n+1)}/\log {n}$

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Discussion Overview

The discussion revolves around evaluating the limit of the expression $\frac{\log {(n+1)}}{\log {n}}$ as \( n \) approaches infinity. It involves mathematical reasoning and exploration of logarithmic properties.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant presents the limit problem and seeks insights on its evaluation.
  • Another participant offers a hint suggesting the use of the expression \( n+1 = n(1+1/n) \) to facilitate the limit calculation.
  • A different participant attempts to solve the limit, breaking it down into components involving logarithmic properties and arrives at a conclusion of 1, while also noting a potential typo in their own work.
  • Another participant agrees with the approach but points out a typo in the third equation of the proposed solution.

Areas of Agreement / Disagreement

There is no consensus on the correctness of the solution, as one participant identifies a typo, indicating that the discussion remains unresolved regarding the final evaluation of the limit.

steven187
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hello all

I was workin on a problem and during my proof I came to this problem does anybody know what happens with this limit

[tex]\lim_{n\rightarrow\infty} \frac{\log {(n+1)}}{\log {n}}[/tex]

thanxs
 
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HINT: n+1 = n(1+1/n)
 
hello all

would this be correct?

[tex]\lim_{n\rightarrow\infty} \frac{\log {(n+1)}}{\log {n}}[/tex]
[tex]=\lim_{n\rightarrow\infty} \frac{\log {n(1+\frac{1}{n})}}{\log {n}}[/tex]
[tex]=\lim_{n\rightarrow\infty} \frac{\log{n}+\log {n(1+\frac{1}{n})}}{\log {n}}[/tex]
[tex]=1+\lim_{n\rightarrow\infty} \frac{\log {(1+\frac{1}{n})}}{\log {n}}=1[/tex]
 
yes that looks right except that you have a typo in the 3rd equation.
 

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