Unleashing the Power of a Mousetrap Engine: max Velocity of 50g Car

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SUMMARY

The discussion focuses on the mechanics of a mousetrap engine powering a small car with a mass of 50 grams, estimating its maximum velocity to be approximately 6.32 m/s. The car is designed to travel 8 meters, utilizing a mousetrap with a maximum force of 10 Newtons at its highest point. The energy conversion from potential energy in the mousetrap to kinetic energy is analyzed, confirming that friction and air resistance will impact the actual velocity. Key calculations utilize the kinetic energy formula KE = 1/2mv² to derive the maximum speed under ideal conditions.

PREREQUISITES
  • Understanding of kinetic energy and potential energy concepts
  • Familiarity with Newton's laws of motion
  • Basic knowledge of energy conversion principles
  • Ability to perform algebraic calculations involving force and mass
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  • Study the principles of energy conservation in mechanical systems
  • Learn about the effects of friction and air resistance on moving objects
  • Explore advanced applications of spring mechanics in engineering
  • Investigate the design and optimization of mousetrap-powered vehicles
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Students, hobbyists, and engineers interested in mechanics, energy conversion, and the practical applications of simple machines in physics experiments.

Craig113
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a ball with the mass of 50 grams hangs on a very light thread who has the length of 80 cm and swing back and forth (pendel). At the beginning of the movement the maximum angle that the thread formed when moving was 35 degress, but after one minute tha angle had declined to 2o degress.The time for the ball to make one swing from its lowest point to its highest remained the same.

The question is: Is the power that the swinging energi (mekanic energi) from the pendel turns into other energi forms under one minute bigger or smaller than the averge power of the pendel?

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A boy has build himself a treehouse that is located 3.8 meters above the groud. He has also build a device that consists of a small platform he can stand on. The platform is attached to a rope that runs throw a
small easily moveable wheel located above the threehouse. With this device the boy can be pulled up to the threehouse by somebody pulling the rope from the ground. The boys mass it 39 kg (boy a), two other boys that help pulling him up have the mass of 34 kg (boy b) and 32 kg (boy c).

Halfway pulling the platform up to the threehouse with boy A standing on it, suddenly boy c let's the rope go, while boy b hang on to it.

the questions are:
a) With what violocity will boy A hit the ground?
b) How high above the ground will boy B go?
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A mousetrap is used as a engine for a small car with the mass of 50 gram.The car mus be able to travel 8 meters. the mousetraps arm is about 4 cm, and it can be pulled 180 degress. The force needed to pull the arm of the mousetrap is linear dependable to the turning angle. its at its lowest point 2 N and on its highest about 10 Newton.

the question is: What it the maximum violocity this car can have?
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Craig113 said:
A boy has build himself a treehouse that is located 3.8 meters above the groud. He has also build a device that consists of a small platform he can stand on. The platform is attached to a rope that runs throw a
small easily moveable wheel located above the threehouse. With this device the boy can be pulled up to the threehouse by somebody pulling the rope from the ground. The boys mass it 39 kg (boy a), two other boys that help pulling him up have the mass of 34 kg (boy b) and 32 kg (boy c).

Halfway pulling the platform up to the threehouse with boy A standing on it, suddenly boy c let's the rope go, while boy b hang on to it.

the questions are:
a) With what violocity will boy A hit the ground?
b) How high above the ground will boy B go?

You can calculate the answer to this problem by considering free body diagrams around each of the two boys and resolving forces, if you assume a frictionless pully and an inelastic rope - both boys will accelerate at the same rate. All you need is F=ma. I started the calculations but need to go, sorry I can't be more help.
 


The content provided discusses the potential of using a mousetrap engine to power a small car with a mass of 50 grams. The maximum velocity of the car is estimated to be 8 meters, and it is mentioned that the force needed to pull the arm of the mousetrap is linearly dependent on the turning angle.

To answer the question of the maximum velocity of the car, we need to consider the principles of energy conversion and conservation. The mousetrap engine converts the potential energy stored in the spring arm into kinetic energy to move the car. The maximum velocity of the car will depend on the amount of energy that can be converted and the resistance or friction acting against the car.

In this scenario, the maximum force exerted by the mousetrap is 10 Newtons, which is at its highest point. This will be the maximum force that can be used to move the car. Using the equation for kinetic energy, KE = 1/2mv^2, we can calculate the maximum velocity of the car.

Assuming all the potential energy of the mousetrap is converted into kinetic energy, we can calculate the velocity using the formula:

10 N = 1/2 x 0.05 kg x v^2

Solving for v, we get a maximum velocity of approximately 6.32 m/s. This is the theoretical maximum velocity that the car can achieve with the given parameters.

However, in reality, there will be factors such as friction and air resistance that will affect the actual velocity of the car. Also, as the mousetrap arm is pulled back, the force decreases, resulting in a lower maximum velocity. Therefore, the actual maximum velocity of the car may be lower than the calculated value.

In conclusion, the maximum velocity of the car using the mousetrap engine can be estimated to be around 6.32 m/s, but in practical terms, it may be slightly lower due to external factors.
 

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