Word Problem: Increasing Solution Strength to 30%

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SUMMARY

The problem involves a tank with a capacity of 90 liters containing a 20% chemical solution. To achieve a final strength of 30%, 15 liters of the 20% solution must be drained and replaced with an 80% solution. The calculation involves setting the total amount of chemical in the final solution equal to the desired concentration and solving for the volume of solution to be replaced.

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  • Understanding of basic algebraic equations
  • Knowledge of percentage concentration calculations
  • Familiarity with the concept of solution dilution
  • Ability to set up and solve linear equations
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  • Study the principles of solution concentration and dilution
  • Learn how to set up and solve linear equations in chemistry
  • Explore real-world applications of chemical mixing problems
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Chemistry students, educators, and professionals involved in chemical engineering or solution preparation will benefit from this discussion.

Diced Tofu
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1. A tank holds 90 L of chemical solution. Currently the solution has a strength of 20%. How much of this should be drained and replaced with an 80% solution to have a final strength of 30%?
 
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Suppose you "drain and replace" X liters of the 20% solution. That leaves 90- X liters of 20% solution. The X liters of the 80% solution will contain 0.8X L of the chemical. The remaining 90-X liters will contain 0.2(90- X) L of the chemical so you will now have 0.8X+ 0.2(90-X) L of the chemical in the final result. How much chemical will there be in 90 L of 30% solution? Set those equal and solve for X.
 
Answer is 15 L.

thx :D
 

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