What is the time needed for A to move 50cm downward?

  • Thread starter Thread starter frozen7
  • Start date Start date
  • Tags Tags
    Time
Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving two masses, A and B, where mass A is subjected to an additional weight to initiate downward movement. The primary questions focus on determining the time required for mass A to move 50 cm downward and the subsequent time for another 50 cm after the weight is removed.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of free body force diagrams and constant acceleration formulas for the first part of the problem. Questions are raised about the effects of removing the weight on A's motion, including whether A continues to accelerate, maintains velocity, or stops.

Discussion Status

The discussion is ongoing, with participants exploring the implications of Newton's First Law on A's motion after the weight is removed. Some guidance has been offered regarding the relationship between forces and motion, but no consensus has been reached on the specific outcomes or calculations.

Contextual Notes

Participants are working under the assumption that the initial conditions and forces acting on mass A are understood, but there is uncertainty regarding the acceleration after the weight is removed.

frozen7
Messages
163
Reaction score
0
https://www.physicsforums.com/attachment.php?attachmentid=4204&stc=1
Both mass of A and B is 0.49kg. A ring of 0.001kg is added on A to let A begin to move downward.
(a) what is the time needed for A to move 50cm downward?
(b)What is the time needed for A to move another 50cm downward if the ring was taken off imediately after first 50cm?


I can find the the answer of (a) but i don't know how to solve the 2nd question since I have no idea at all about how to find out the acceleration after first 50cm. Can anyone help me?
 

Attachments

Physics news on Phys.org
I assume you did some free body force diagrams and analysed them for the first part?
A had the extra weight and so due to f=ma began to move.
I assume you then used constant acceleration formulae to calculate the time it took for A to move 50cm.

Now...

After the first 50cm, the weight is removed. What does this mean in terms of the equating of forces?... Does A still accelerate? Does it stop dead? Does it keep the same velocity?
Think about Newton's First Law : An object will remain at rest or at constant velocity unless acted upon by an external force.
 
A is still moving ...is it still accelerate with the same acceleration as previous?
How does Newton`s First Law relate with this question?
 
frozen7 said:
A is still moving ...is it still accelerate with the same acceleration as previous?
How does Newton`s First Law relate with this question?
"An object will remain at rest or at constant velocity unless acted upon by an external force."

After the additional weight is removed, there is no (net) external force- A will continue to move with no acceleration but at the speed it had at 50 cm.
 
Thanks. Is the answer equal to 5s?
Assume s=0.5
u= the speed at first 50cm
a=0
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
34
Views
3K
Replies
3
Views
5K
Replies
30
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
4K
Replies
13
Views
2K