Find a root for this expression:

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Discussion Overview

The discussion revolves around finding a root for the expression cos(x) + cos(ix) + cos(x*i^3/2) + cos(x*i^1/2) = 0 for x. Participants explore the possibility of an analytic solution and the nature of potential roots, including complex roots.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant suggests that an analytic root may not exist and proposes an approximate value related to (8 factorial)^(1/8).
  • Another participant expresses doubt about the existence of a root, noting that x = 0 is closer to a solution than a previously suggested value of x = 3.764350600.
  • A different participant realizes that the root must be complex, specifically of the form i^1/4, and questions the existence of a formula for cos(x) + cos(y) + cos(z) similar to the product formula for two cosine terms.
  • One participant shares results from 3D plots and the FindRoot function in Mathematica, indicating that they found an approximate root at 1.4405686011239758 - 3.477840254362339i.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the existence of an analytic solution or the nature of the roots, with multiple competing views presented regarding the potential for complex roots and the effectiveness of various approaches.

Contextual Notes

There are limitations regarding assumptions about the nature of the roots and the applicability of known formulas for trigonometric sums. The discussion includes unresolved mathematical steps and the complexity of the expression involved.

MaxwellPhill
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cos(x)+cos(ix)+cos(x*i^3/2)+cos(x*i^1/2)=0 for x

I have spent a lot of time finding an analytic root to this equation without success. An analytic root may not exist. I don't know. It is roughly equal to (8facorial)^(1/8)
 
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I don't think there is an anaylitical solution and I am not sure that there even is a root.

x = 0 is closer than your x = 3.764350600, but that's only taken it down to 4 rather than 8.0003108.
 
Hmm..I ust realized for the expression above the root must be complex of the form i^1/4.

Trig functions of the form cosx+cosy =0 can be solved because of the product formula:

cos(x)+cox(y)=2*(cos((x+y)/2))*(cos((x-y)/2)))

but is there such a formula for cos(x)+cos(y)+cos(z) ?
 
I did some 3D Plots in mathematica to get a rough idea where a root might be and then used the FindRoot function and got that 1.4405686011239758 - 3.477840254362339i is approximatly a root.

I don't think there is any simplification like you want.
 

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