How much work is done in moving a mole of electrons around a circuit

[hyperdrive]

i know this is basic suff, but forget it, can u please tell me how to do this question



how much work is done in moving a mole of electrons around a circut using a 6v voltage( 1 mole of electrons is 6.023 x 10 power 23 electrons


thanks

answer is w = qv = 5.78 x 10power5j

 

[Nylex]

Do you know the charge on an electron? To find the total charge, q, multiply the charge of one electron by the number of electrons...

 

[hyperdrive]

yes the charge of an eleectron is -1.6 x10power-19

sorry don't understand,

v =w/q

w=vq

v is potential difference in volts
w is work done by field in joules
q is charge being ppushed in coulombs


so w= 6 x q( which i thought was the mole of electrons, which is 6.023 x 10power23 right?)

 

[Nylex]

If you know q is charge, as measured in coulombs, why would you think it was 6.022 x 10^23, which is the number of electrons?

If you had one electron, the work done would be, W = QV = (1.6 x 10^-19)*6..

 

[hyperdrive]

k, got confused there, i hate this topic, i like the space one!

i see now:) so


w = 6* ( 1.6 x 10^-19 x number of electrons (6.023 x 10^23)

 

[Nylex]

Yes, that's correct .

 

[hyperdrive]

thanks, i have been lazey thesee holidays:P

seen these forums once before and when i formated my computer i lost the address, just found it again, i quess this is British forum(the mother land!)