REally confused Need Help on electric charges and Coulomb's Law

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SUMMARY

This discussion focuses on solving problems related to electric charges and Coulomb's Law. Key calculations include determining the distance between two charges of 2.0μC that exert a force of 4.0x10^-4 N, resulting in a separation of 1 cm. Additionally, the force on three equal charges of +6.0μC spaced 0.23 m apart is calculated to be 1.33x10^-4 N per charge. The discussion also addresses the mutual repulsive force between two positively charged spheres and the force on point charges arranged in a square configuration, emphasizing the application of Coulomb's Law.

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  • Coulomb's Law
  • Understanding of electric charge units (μC)
  • Basic algebra for solving equations
  • Vector addition of forces
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Electric Charges and Coulomb’s Law

Guys, help me solve these problems. I'm really in big trouble.. thanks guys!

a)Two charges of equal magnitude exert an attractive force of 4.0x10-4 N on each other. If the magnitude of each charge is 2.0μC, how far apart are the charge?

b)Three equal charges, each of +6.0μC, are spaced along a line. The end charges are each 0.23 m from the central charge. What are the magnitude and direction of the force on each charge?

c)Two small, positively charged spheres experience a mutual repulsive force of 1.52 N when their centers are 0.200 m apart. The sum of the charges on the two spheres is 6.00μC. What is the charge on each sphere?

d)Four equal point charges +q are placed at the corners of a square of edge length L. Find the force on anyone of the charges.

e)Two equally charged insulating balls each weigh 0.10g and hang from a common point by identical threads 30cm long. The balls repel each other so that the separation between their center is 6.4 cm. What is the magnitude of the charge on each ball?
 
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a) Simply use Columb's law. :confused:

b) Same thing, just add forces as vectors.

c) There is an equation used to calculate this. It is surely in your textbook.

d) Same as b), only in 2D

e) Use equilibrium of forces.
 


a) To solve this problem, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, we are given the force (4.0x10^-4 N), the magnitude of each charge (2.0μC), and we need to find the distance between them. So, we can set up the equation as follows:

F = k * (q1 * q2)/d^2

Where F is the force, k is the Coulomb's constant (9x10^9 Nm^2/C^2), q1 and q2 are the two charges, and d is the distance between them.

Plugging in the given values, we get:

4.0x10^-4 N = (9x10^9 Nm^2/C^2) * (2.0μC)^2/d^2

Solving for d, we get:

d = 0.01 m or 1 cm

Therefore, the two charges are 1 cm apart.

b) To solve this problem, we can again use Coulomb's Law. Since the charges are all equal, we can use the same equation as in part a). However, we need to find the force on each charge, so we can divide the total force by 3. Also, since the charges are all positive, the force will be repulsive.

So, the force on each charge will be:

F = (4.0x10^-4 N)/3 = 1.33x10^-4 N

c) In this problem, we are given the force and the distance between the charges, and we need to find the charge on each sphere. Again, we can use Coulomb's Law, but this time we have two unknowns (the two charges). So, we need to set up two equations using the given information and then solve for the two charges.

From the given information, we know that:

F = k * (q1 * q2)/d^2

And the sum of the charges is 6.00μC, so we can write:

q1 + q2 = 6.00μC

Now, we can substitute the value of F from the first equation into the second equation and solve for one of the charges. Then, we can
 

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