Help Electric field and Potential

[nutzweb]

Electric Field and Potential

help me in answering these questions. sorry guys, not really good at physics.. thanks for the BIG help!

a)Two large metal sheets carrying equal and opposite electric charged are separated by a distance of 52.0 mm. The electric field between them is uniform and has a magnitude of 670 N/C.
i)What is the potential difference between the sheets?
ii)Which sheet is at higher potential, the one with positive charge or the one with negative charge?

b)A proton of charge q=1.60x10-19 C is placed in a region of uniform electric field with field strength E=1.46x105 N/C. What is the electrostatic force on the proton?

c)Three equal positive point charges of magnitude Q are located at three corners of a square of edge length d. A negative charge –3Q is placed on the fourth corner. At the position of the negative charge, what is the magnitude of the electric field due to the three positive charges? What is the force on the negative charge?

d)Four equal point charges of magnitude Q are arranged on the corners of a square of edge length 1.0 cm. Evaluate the electric field at the center and the midpoint of one edge, given that Q=1.0x10-9 C.

 

[Nylex]

You need to show us what you've done so far (or at least, some of your ideas/thoughts on how to answer these).

 

[thepatientmental]

a) i) The potential difference between the two sheets can be calculated using the formula V = Ed, where V is the potential difference, E is the electric field strength, and d is the distance between the sheets. Plugging in the values, we get V = (670 N/C)(0.052 m) = 34.84 V.

ii) The sheet with negative charge is at a higher potential. This is because electric potential is defined as the amount of work needed to bring a unit positive charge from infinity to a point in the electric field. Since the negative charge repels positive charges, it takes more work to bring a positive charge closer to the negative sheet, thus it has a higher potential.

b) The electrostatic force on the proton can be calculated using the formula F = qE, where F is the force, q is the charge of the proton, and E is the electric field strength. Plugging in the values, we get F = (1.60x10^-19 C)(1.46x10^5 N/C) = 2.34x10^-14 N.

c) At the position of the negative charge, the magnitude of the electric field due to the three positive charges can be calculated using the formula E = kQ/r^2, where k is the Coulomb's constant, Q is the magnitude of each positive charge, and r is the distance from the charge to the point. Since the three positive charges are equidistant from the negative charge, the distance r is equal to the length of the square's diagonal, which can be calculated using Pythagorean theorem as d√2. Therefore, E = (9kQ)/(d^2).

The force on the negative charge can be calculated using the formula F = qE, where F is the force, q is the charge of the negative charge, and E is the electric field strength. Plugging in the values, we get F = (-3Q)(9kQ)/(d^2) = -27kQ^2/d^2.

d) At the center of the square, the electric field can be calculated using the formula E = kQ/r^2, where k is the Coulomb's constant, Q is the magnitude of each charge, and r is the distance from the center to each charge. Since all four charges are equidistant from the center, the distance r is equal to the length of