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To integrate functions as the limit of an integral sum, how can we know which way to take the partition points in the interval?
For example, in
[tex]\int_{a}^{b} x dx[/tex]
I can take the partition points as
[tex]x_o = a[/tex]
[tex]x_1 = a + \delta x[/tex]
...
[tex]x_k = a+ k\delta x[/tex]
where [tex]\delta x = \frac{b-a}{n}[/tex]
So that the sum is [tex]\sum_{k=1}^{n} f(x_{k-1}) \delta x[/tex]
But to integrate
[tex]\int_{a}^{b} \sqrt{x} dx[/tex]
If I take the partition points as above the sum will be
[tex](\delta x)(\sqrt{a} + \sqrt{a+ \delta x} + ... )[/tex]
which I cannot find.
I can solve the question if I take the partition points as
[tex]x_0 = a[/tex]
[tex]x_1 = aq[/tex]
...
[tex]x_k=aq^k[/tex]
Where [tex]q=(\frac{b}{a})^(1/n)[/tex].
{The idea to take it this way was given as a hint in the book}
So, is there any other specific manner in which I should spilt the partition points and if so is there a general method in which I can know how to take the values of x_0, x_1, x_2 to solve the problem?
For example, in
[tex]\int_{a}^{b} x dx[/tex]
I can take the partition points as
[tex]x_o = a[/tex]
[tex]x_1 = a + \delta x[/tex]
...
[tex]x_k = a+ k\delta x[/tex]
where [tex]\delta x = \frac{b-a}{n}[/tex]
So that the sum is [tex]\sum_{k=1}^{n} f(x_{k-1}) \delta x[/tex]
But to integrate
[tex]\int_{a}^{b} \sqrt{x} dx[/tex]
If I take the partition points as above the sum will be
[tex](\delta x)(\sqrt{a} + \sqrt{a+ \delta x} + ... )[/tex]
which I cannot find.
I can solve the question if I take the partition points as
[tex]x_0 = a[/tex]
[tex]x_1 = aq[/tex]
...
[tex]x_k=aq^k[/tex]
Where [tex]q=(\frac{b}{a})^(1/n)[/tex].
{The idea to take it this way was given as a hint in the book}
So, is there any other specific manner in which I should spilt the partition points and if so is there a general method in which I can know how to take the values of x_0, x_1, x_2 to solve the problem?