25N Sideways Force on 10kg Box: F = m*a Formula Error

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Homework Help Overview

The discussion revolves around a scenario involving a 25N sideways force acting on a 10kg box moving at a constant speed of 5 m/s. Participants are exploring the implications of this force in relation to Newton's second law of motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to determine the net force acting on the box, questioning whether friction is a factor and considering the implications of constant velocity on net force.

Discussion Status

The discussion is actively exploring the relationship between force, mass, and acceleration. Some participants have provided insights regarding the effects of constant velocity on net force, suggesting that the net force may be zero under these conditions. There is an acknowledgment of a hint that encourages deeper consideration before applying equations.

Contextual Notes

Participants are navigating the implications of the problem's setup, particularly regarding the presence of friction and the interpretation of constant velocity in relation to net force.

mystry4
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If you have a 25N sideways force on a 10kg box that moves at speed of 5 m/s, what is the formula? I used F = m*a and got it wrong. :confused:
 
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What are you being asked to find out?
 
I am being asked to find the net force on the box.
 
well, so far the only force acting on it is the 25 N,
Is there friction?
 
Also, if the box is moving with constant velocity, i.e. no acceleration, then the net force is zero.
 
Well that makes sense...and probably why a HINT was put in there (HINT: Think about this a bit before writing down any equations!)
So, I amanswering that the net force is O because of continual velocity and no acceleration.
Thank you for your help
 

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