Finding the Height Function for y=\frac{-1}{X^2} + 4

[bayan]

Hi guys.

I was doing a SAC and there were two questions

one was $$y=\frac {1}{X^2}-1$$ and the other was $$y=\frac {-1}{X^2}+4$$

I got the height function to be $$h=e^\frac{V}{\pi}-1$$ where V is the volume and max height is 3 for the first function $$y=\frac {1}{X^2}-1$$

Can someone help me to find the height function of the other function please.


The Volume of both graphs are same.


Thanx in advance.

 

[bayan]

is this the height function of second function? $$h=e^\frac{-V}{\pi}-4$$

 

[matt grime]

would you mind defining a 'height' function. I can find no references for it (other than misspelling it as height when it is defined for abelian groups according to planet math)

 

[HallsofIvy]

Hi guys.

I was doing a SAC and there were two questions

one was $$y=\frac {1}{X^2}-1$$ and the other was $$y=\frac {-1}{X^2}+4$$

$$y= \frac{1}{X^2}-1$$ is not a question- it is a function or equation. What was the question??

I got the height function to be $$h=e^\frac{V}{\pi}-1$$ where V is the volume and max height is 3 for the first function $$y=\frac {1}{X^2}-1$$

Can someone help me to find the height function of the other function please.


The Volume of both graphs are same.


Thanx in advance.

I didn't know a graph had a volume! I assume "height" was a misprint for "height" but I'm still not sure what you mean by the "height" of a function.

 

[bayan]

$$y= \frac{1}{X^2-2}-1$$ is not a question- it is a function or equation. What was the question??



I didn't know a graph had a volume! I assume "height" was a misprint for "height" but I'm still not sure what you mean by the "height" of a function.

Sorry about my BAD english but all I intended to say is how can I find the rate of change of height with respect to change in volume from the second equation.


Hope that makes it abit more clear.