Model RL Circuit: Why "RI" & Not "dI"?

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Discussion Overview

The discussion revolves around the modeling of an RL circuit, specifically questioning why the term "RI" is used instead of "dI" in the equation L(dI/dt) + RI = V. Participants explore the roles of current and its change in relation to resistors and inductors.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant asserts that the correct modeling equation for an RL circuit is L(dI/dt) + RI = V and questions the use of "I" instead of "dI".
  • Another participant suggests that if there were no inductor, "dI/dt" would not be necessary.
  • Some participants argue that since there is an inductor, "I" should be "dI", prompting a discussion about the nature of current in the circuit.
  • It is noted that the voltage drop across an inductor is proportional to the change in current, while the voltage drop across a resistor is proportional to the current itself, which is reflected in the modeling equation.
  • One participant expresses confusion about whether current is always changing, questioning the necessity of "I".
  • A later reply clarifies that in a resistor, the voltage is proportional to the instantaneous current, while in an inductor, the voltage relates to the derivative of magnetic flux, leading to the conclusion that the voltage in a circuit is derived from the change in current.

Areas of Agreement / Disagreement

Participants express differing views on whether "I" should be represented as "dI" in the context of an RL circuit, indicating that multiple competing views remain and the discussion is unresolved.

Contextual Notes

Some participants highlight the importance of distinguishing between instantaneous current and the change in current, but the discussion does not resolve the implications of these distinctions for the modeling equation.

asdf1
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if you model a RL-circuit, the correct answer should be L(dI/dt)+RI=V
but why doesn't the "I" in "RI" have to be "dI"?
 
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If ther were no inductor, would you need (dI/dt)?

Regards
 
no, but in that case there is an inductor,
so shouldn't the "I" be "dI"?
 
asdf1 said:
no, but in that case there is an inductor,
so shouldn't the "I" be "dI"?
Think of two circuits; one with just a resistor and one with just an inductor (ideal with no resistance).
 
Such terms are not arbitrarily assigned. The voltage drop across an inductor is directly proportional to the CHANGE in current. The voltage drop across a resistor is proportional to the CURRENT. This is reflected in the modeling equation which must be based on the physics of the system.
 
@@a
still a little confused~
but isn't the current always changing?
so there isn't supposed to be "I"?
 
In a resistor the instant voltage is proportional to the instant current:[tex]v(t) = R i(t)[/tex] (Ohm's law).
In an inductor, the instant magnetic flux is proportional to the instant current: [tex]\phi(t) = L i(t)[/tex].
But by Faraday's law, the voltage in a circuit is the derivative of the flux: [tex]v(t) =\frac{d\phi}{dt}[/tex], so [tex]v(t) =L\frac{di}{dt}[/tex].
 
thanks~
i think i thought too much...
:P
 

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