Solving Pressure Problems: Vacuum Cleaner & Octopus

  • Thread starter Thread starter psycovic23
  • Start date Start date
  • Tags Tags
    Pressure
Click For Summary

Homework Help Overview

The discussion revolves around pressure-related problems involving a vacuum cleaner and an octopus. The original poster presents two scenarios: calculating the weight of a brick that a vacuum cleaner can lift and determining the force an octopus can exert using its sucker in salt water at a specific depth.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the need to determine the pressure generated by the vacuum cleaner and how it relates to the area over which this pressure acts. There is uncertainty about whether the pressure can be assumed or needs to be provided. The original poster expresses confusion about how to approach both parts of the problem.

Discussion Status

Some participants have offered guidance on the relationship between pressure, area, and force, suggesting that the pressure of the vacuum cleaner is crucial for solving the first part. There is an acknowledgment of the vacuum's operational principles, with one participant clarifying that it is the external air pressure that contributes to lifting the brick.

Contextual Notes

The original poster notes a lack of information regarding the pressure generated by the vacuum cleaner, which is central to solving the first part of the problem. Additionally, the depth of the salt water in the second part introduces further considerations regarding pressure calculations.

psycovic23
Messages
47
Reaction score
0
(a) A very powerful vacuum cleaner has a hose 2.86cm in diameter. With no nozzle on the hose, what is the weight of the heaviest brick it can lift? (b) A very powerful octopus uses one sucker, of diameter 2.86cm, on each side of a shell of a clam in an attempt to pull the shells apart. Find the greatest force the octopus can exert in salt water 32.3m deep.

(a) - I'm not sure how I know the power of the vacuum, but I think I'm suppose to use [tex]P = P_0 + pgh[/tex] although I'm not sure how.

(b) I have no clue how to do this :-\

Could anyone lend a hand?
 
Physics news on Phys.org
For the first part you need to know what pressure the vacuum cleaner is generating.

Once you have this you need to think about over what area this pressure is acting.

Remember

Pressure * Area = Force

And the force relates to the weight.

The second part is not so different... :smile:
 
Well, the problem doesn't give me the pressure of the vacuum. Is that something I can assume?
 
Of course, a vacuum cleaner doesn't actually pull anything- it reduces the density of air in it and then the pressure of the outside air pushes things in.
The minimum possible density is, of course, 0 which would result in the air pressure (one atomosphere) pushing against the brick. Multiply standard one atmospher air pressure by the area of the hose to find the maximum possible force.
 

Similar threads

Replies
10
Views
9K
Replies
1
Views
3K
Replies
4
Views
7K
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
8K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 8 ·
Replies
8
Views
7K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
8
Views
2K
Replies
9
Views
5K