Solving Laplace and Heat Equation in 3D Rectangular Solid

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Homework Help Overview

The discussion revolves around solving the heat equation in a three-dimensional rectangular solid defined by specific initial and boundary conditions. The original poster seeks assistance in finding the temperature function T(x,y,z,t) that satisfies the given Laplace equation and conditions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of the initial condition T(x,y,z,0)=0, questioning whether this leads to a trivial solution. Some suggest methods for solving the boundary conditions, while others express difficulty in addressing specific variables.

Discussion Status

There is a mix of responses, with some participants suggesting that the trivial solution may be the only one available, while others propose methods for approaching the problem. The conversation reflects a lack of consensus on the interpretation of the boundary conditions and their relevance to the solution.

Contextual Notes

Participants note potential confusion regarding the boundary conditions and the initial condition, with some questioning if there are any typographical errors in the problem statement that could affect the solution.

danai_pa
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Heat equation

Given the 3-D rectangular solid with sides of length a, b and c in the x, y and z directions, respectively. Find the function T(x,y,z,t) when
Laplace(T)=1/K(dT/dt) subject to the following conditions:

1) Initial conditions: T(x,y,z,0)=0
2) Boundary conditions
a. dT/dx + h(1)T = 0 for x=0
b. T = 0 for x=a
c. dT/dy = 0 for y=0
d. dT/dy = 0 for y=b
e. dT/dz = 0 for z=0
f. dT/dz + h(2)T = 0 for z=c

Anyone plese suggest me, I don't understand. Thank you.
 
Last edited:
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?? What have you tried? I don't see any reason why T(x,y,z,t) identically equal to 0 isn't the solution. It satisfies all the conditions, doesn't it?
 
HallsofIvy: it is, but it's the trivial one.. it's a linear equation, the solution can be multiplied by a constant, and knowing that 0 is a good solution doesn't give you anything..
danai_pa:
try the following steps:
1) solve the boundary. you'll see that on the three of the faces of the cube , T is zero and on all the rest, its derivative is zero
2) write T as
sum C(n,m,l) sin(pi n x/a) cos(pi m y/b) cos(pi (l+1/2) z/c)
it is a general way to write the function taking care of the constraints automatically
3) now, just calculate the time dependence of C(n,m,l) by applying laplacian to the general notation (pay attention that the functions of the series are orthogonal)
 
please help

I can solve this equation for y only and x , z. I can't find it. Please describe to me. Thank you.
 
please help

Anyone please help me. I can not solve it.
Thank you
 
Clearly the "existence and uniqueness" theorem applies to this. T(x,y,z,t) identically equal to 0 may be trivial but it's the only one you're going to get!
 
Actually i didn't pay attention to the condition T(x,y,z,0)=0, which really makes the problem trivial (T=0 always), but if it's so, the boundary conditions have absolutely no meaning.. are you sure there's no typo?
 
I can solve variable of x and y but variable z i can not solve it.
Anyone please suggest me. Thank you
 
  • #10
Read back through this. You have already been told the solution several times!

It really doesn't matter whether the variables are x, y, z, or anything else.
 

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