Calculating Acceleration & Force of Strain Thread

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Homework Help Overview

The discussion revolves around calculating the acceleration of weights and the force of a strain thread, as presented in a specific exercise from a textbook. Participants are attempting to clarify the problem and explore the underlying physics concepts involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the clarity of the original question and the assumptions made regarding the system of weights and pulleys. There is an emphasis on defining accelerations in relation to different components of the system and applying Newton's laws.

Discussion Status

Some participants have provided insights into the relationships between the accelerations of the various masses and the movable pulley. There is an ongoing exploration of the problem, with no clear consensus yet on the correct approach or solution.

Contextual Notes

Participants note that the original poster has referenced a textbook exercise and indicated that their previous solution was incorrect, which may influence the discussion's direction. The clarity of the question and the necessity for showing prior attempts are also under scrutiny.

irrehaare
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J must count acceleration of each weight and the force of strain thread. Here is a picture:
 

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so nobody know the answer or i wrote quastion to complicated ?
 
Well, for one thing your question is not very clear! What are you trying to do?For another, this is the homework forum and you haven't shown that you have tried anything yourself!
 
of cours i tried but it is a exercaise from book and i have an answer at the end. But my solution is incorrect. So i ask here. And i tried to count forces work on thread on my picture.
 
Uhmm, let a0 be the acceleration of the movable pulley with respect to the ground.
Positive direction downward.
Let a1 be the acceleration of the m1 with respect to the ground.
Let a'2 be the acceleration of the m2 with respect to the movable pulley (that's how the m2 moves in the movable pulley's view).
Let a'3 be the acceleration of the m3 with respect to the movable pulley (that's how the m3 moves in the movable pulley's view.).
So the acceleration of m2 with respect to the ground is a2 = a'2 + a0, the acceleration of m3 with respect to the ground is a3 = a'3 + a0.
And you have a0 = -a1 (The acceleration of the movable pulley and the m1 is the same in magnitude but in opposite direction).
Since the mass of the movable pulley is negligible, the resultant force acts on it must be [itex]\vec{0}[/itex].
You can use Newton's 2nd law to solve this problem.
Viet Dao,
 

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