Is the Neumann Series Always Effective for Solving Integral Equations?

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SUMMARY

The discussion centers on the effectiveness of the Neumann Series for solving integral equations of the form \(\int_{a}^{b}dyK(x,y)f(y)=g(x)\). The user employs a resolvent Kernel \(R\) defined by the Neumann series \(R=\sum_{n=0}^{\infty}b_{n}(K-I)^{n}\) to derive \(f(x)\) from the known function \(g(x)\). Participants confirm that this approach is valid, although it may be tedious in certain scenarios.

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eljose
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Let be the integral equation:

[tex]\int_{a}^{b}dyK(x,y)f(y)=g(x)[/tex]where f is unknown and g is known, then i use a resolvent Kernel in the form:

[tex]\int_{a}^{b}dyR(x,y)g(y)=f(x)[/tex] where we obtain the Kernel R by:

[tex]R=\sum_{n=0}^{\infty}b_{n}(K-I)^{n}[/tex] the last is Neumann series for the Kernel operator R..is my approach always true?..thanks.
 
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Yes, that will work. It's a bit tedious in some cases.
 

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