How to Calculate Frictional Forces and Acceleration in a Physics Problem

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SUMMARY

This discussion focuses on calculating frictional forces and acceleration in physics problems involving a block and a calculus book. The first problem involves a 3.3 kg block pushed by a 20 N force at an angle of -40°, with a coefficient of kinetic friction of 0.25, leading to a calculated frictional force of 10 N and an acceleration of 1.5 m/s², which were incorrect. The second problem involves a 3.5 kg book pushed by a 25 N force, where the expected coefficient of kinetic friction is 0.58, but the calculations provided by the user were incorrect. The user expressed confusion over their calculations despite following similar methods to those used in a textbook example.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of frictional force calculations
  • Ability to perform vector resolution of forces
  • Familiarity with kinematic equations
NEXT STEPS
  • Review the derivation of the frictional force formula: fk = ck * Fn
  • Study the application of Newton's Second Law in multi-force scenarios
  • Learn how to resolve forces into components, particularly in angled force applications
  • Practice solving kinematic equations for acceleration and velocity
USEFUL FOR

Students studying physics, particularly those tackling problems involving forces, friction, and acceleration. This discussion is beneficial for anyone preparing for exams or needing clarification on applying physics concepts in practical scenarios.

fiestytig
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Here's my first question:

A 3.3 kg block is pushed along a horizontal floor by a force F of magnitude 20 N at an angle = -40°. The coefficient of kinetic friction between the block and floor is 0.25.

(a) Calculate the magnitude of the frictional force on the block from the floor.
(b) Calculate the magnitude of the block's acceleration acceleration.

This problem is adapted from a book problem. The figures in the book are: m=3.5 kg, angle = -40; ck=.25. I worked that one and got answers that agreed with the book (a) 11 N (b) .14 m/s2. Plugging the different number into the same problem does not give me answers that are correct! Here's what I did for the book problem:

(a) I first found T using equation substitution like in problem 6-2. I
used T to find Fn and Fn to find fk. For the book problem, I got 11 N,
which is correct per the book. For the homework assignment, I got 10 N,
which is not correct. I checked my math, and I'm not doing anything
differently. What am I missing?

(b) I drew a diagram to show the different forces and decided there's only
acceleration along the x axis, so I only needed to consider horizontal
forces: F and fk. I calculated Fx = F cos A. I figured a = (Fx - fk)/m.
I got .14 m/s2, which is what the book has. I did the same calculations
for the online assignment and got 1.5, which is not correct. I again
checked my math, and I'm not doing anything differently. But what am I
doing wrong?

Thanks,
the spelling-challenged fiestytig
 
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My second question that I need help with:

In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.5 kg book is pushed from rest through a distance of 0.90 m by the horizontal 25 N force from the broom and then has a speed of 1.60 m/s, what is the coefficient of kinetic friction between the book and floor? Book says answer is .58. I can't get that.

What I tried: I figured I could probably find acceleration and then divide that by gravity to get the coefficient. So I plugged in: 1.6^2 = 2*.9 * a, a=1.42. I tried dividing that by gravity, got .14 - no good. I decided I needed to use the m value and the F value given, so thought maybe I needed to go about it like this:
F + fk = ma = 25 + ck*9.8 = 3.5 * 9.8 * ck, ck = .98. Wrong again. Looked through 2 Physics books for other things to try, but got nothing. What am I doing wrong here?
 
Nobody wants to play with friction tonight? :(
 

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