Solving the Limit as x Approaches pi/2

[thenewbosco]

this one looks simpler but i need another one of those tricks i guess:

the limit as x-->pi/2 from the left of:

$$\frac{tan x}{ln(cos x)}$$

after taking l'hopital once and simplifying i have ended up with

$$\frac{1}{sin x cos x}$$

next is what i don't know

 

[thenewbosco]

wait never mind i thought of my own trick that works..multiply by 2/2 and use sin2x in the denom.