Particle Motion between Parallel Walls: Speed & Angle

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SUMMARY

The discussion focuses on the motion of a particle traveling between two parallel vertical walls separated by 6.7 meters, with a constant horizontal speed of 5.3 m/s. Upon impact with the opposing wall, the particle's speed is calculated to be 8.152 m/s, and the angle of impact is determined to be 49.447 degrees relative to the vertical wall. Clarifications reveal that the angle should be measured with respect to the vertical, not the positive x-axis, addressing confusion regarding the trajectory's angle.

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A particle travels btwn 2 parallel vertical walls separated by 6.7m. It moves towards the opposing wall at a constant rate of 5.3m/s. It hits the opposite wall at the same height. The acceleration of gravity is 9.8m/s^2.

The first question pertaining to this was the speed when it hits the opposing wall. I found the correct answer to be 8.152m/s. Then it wants to know the angle that it hits the wall. For where the particle left the first wall, I made a right triangle and found the angle to be 49.447 degrees.

I don't know how to answer the question. I assumed that the answer was to be in respect to the positive x-axis so I did 180-49.447 = 130.553 and that was wrong. Are they asking for the angle relative to the opposing wall? I'm so confused.
 
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What they want is the angle that the trajectory makes with the wall. Since the wall is vertical, the angle is with respect to vertical, not the x-axis.
 
" It hits the opposite wall at the same height. "

Same height?? Same as what? No height is mentioned.

Also you say "It moves towards the opposing wall at a constant rate of 5.3m/s." That can't be true if there is acceleration due to gravity.

Did you intend to say that the horizontal component of velocity is a constant 5.3 m/s?
 

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