Solving Friction Problem in Physics - Cns/Oslo

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Homework Help Overview

The discussion revolves around a physics assignment involving two objects on a horizontal table connected by a rope, focusing on the calculation of friction coefficients and the application of Newton's second law.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the appropriate friction coefficient to use in their calculations and questions whether to integrate the coefficients or calculate them individually. Some participants suggest applying Newton's second law to each object separately while considering their shared acceleration.

Discussion Status

Participants are exploring different approaches to the problem, with some guidance provided on applying Newton's second law and considering the frictional forces for each object. There is no explicit consensus, but productive direction has been established.

Contextual Notes

The original poster mentions a deadline for the assignment and expresses uncertainty about their understanding of the problem, indicating a need for clarification on the concepts involved.

Oslo
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Hello!

I have just started physics here in Norway, and we have a home assignement due to friday. I sat all yesterday trying to figuer out what friction coefficient to use in my assignment. Here is the assignment:

Two objects are lying on an horizontal table, tied together with a very light rope, object 1 has the mass of 2Kg and object 2 has the mass of 4Kg.

Object one has friction coefficient = 0.1
Object two har friction coefficient = 0,15

The Force applied on the rope tied to object 2 has a force of 60N...

Object 1----------object 2----------------> F=6N

Do i calculate with 0.25 as a friction coef.? or both individually intergrated into F-(Mju*g+(m1+m2)/(m1+m2) . To find the acceleration

Please give me some hints.

Hopefully you understand my english :)

thanks
Cns/Oslo
 
Last edited:
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Consider each object separately. Apply Newton's second law (the sum of all of the forces that an object experiences is equal to it's mass times it's acceleration) for each object separately in the direction of F. Each object has it's own frictional force (which can be calculated). Both objects share the same acceleration though. You will end up with two equations with the same tension in both. Add the two equations up and solve for the acceleration.
 
Thank you so much, you have been to great help!
 
Glad I could help you.
 

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