Confused by a High School Physics Problem? Discover the Missing Equation!

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Homework Help Overview

The discussion revolves around a physics problem involving average speed and average velocity during a round trip. The original poster expresses confusion regarding the calculations needed to determine the average speed over the entire trip, given two different speeds for each leg of the journey.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to set up equations based on the distances and speeds but notes a lack of a third equation to solve for the unknowns. Some participants suggest that one of the unknowns cancels out, leading to a simpler calculation for average speed.

Discussion Status

Participants are engaging in a productive dialogue, with some providing insights into the problem setup and calculations. There is acknowledgment of the original poster's confusion, and a participant has offered a potential resolution regarding the average speed calculation.

Contextual Notes

There is an indication that the problem may have been perceived as too challenging for high school students, raising questions about the appropriateness of the assignment. The original poster's uncertainty about their own understanding of the problem is also noted.

physmurf
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I assigned a couple of problem to my students today without realizing that these would be too difficult for high school students. However, after starting the problem, I got stumped. I know I am missing something, but what is it? The problem reads as follows:

5. A person walks first at a constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is
a. her average speed over the entire trip and
b. her average velocity over the entire trip?

Part b is simple, but 'a' is where I got stuck. You know delta x is the same, and you know that t1 and t2 will be different as well.

So, delta x = v1*t1, and x=v2*t2.

However this leaves us with three unknowns and two equations.

What am I missing for my third equation?

Thanks!
 
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x= distance traveled from A to B
v_1=5 m/s
v_2=3 m/s

x=5t_1
x=3t_2

t_1=x/5
t_2=x/3

avg. speed = distance/total time= 2x/(t_1 +t_2)=(2x)/(x/3+x/5)=3.75 m/s

one of your unknowns simply cancels out.

since the average speed will be the same no matter what the distance, it is unimportant what the distance between a and b are.
 
Last edited:
Thanks,

I knew it was something like that.
 
Okay, so we are all relieved that the problem has a well-defined answer!

Are you telling us that you assigned this problem to your students without knowing how to do it yourself?


I agree that this problem is not too difficult for high school students- but I'm wondering about you!
 

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